Question

Halp me plss halp me plss

Answer 1

Answer:

Your answer is 20

Question is telling to find hypotenuse.

Consider Perpendicular as 16 and Base as 12

Use The Pythagoras theorem

Pythagoras theorem =hsquare=psquare+bsquare.

Answer 2

Answer:

$20$

Skills needed: Pythagorean Theorem

Step-by-step explanation:

1) First, we are given a right triangle.

---> We know this, as there is one right angle in the triangle (marked with the square-like shape -- $\angle ABC$).

An important term to know is: Hypotenuse

---> This is the side of the triangle opposite of the right angle.

In this case, that is the side we are solving for.

2) Now, we know we are solving for the hypotenuse, but trying to solve for it is difficult without the Pythagorean Theorem.

---> This theorem allows you to solve for any side of the right triangle when given 2 side-length values.

The formula is: $a^2+b^2=c^2$

$a$ = one of the legs (not opposite the right angle)

$b$ = another of the legs (also not opposite the right angle)

$c=$ hypotenuse (opposite of the right angle)

3) In this problem, we are given the two legs.

---> Now, if you are unfamiliar with this term, legs are the two sides in a right triangle that are not opposite of the right angle.

---> They are the two shorter sides.

----> In this problem they are: $12$ and $16$

Let's plug those in for $a$ and $b$ and solve! (below)

4) $a^2+b^2=c^2$

$a=12, b=16$

$(12)^2+(16)^2=c^2$ --> Substituting in for the two legs.

$144+256=c^2$ --> Simplifying the exponents

$400=c^2$ --> Adding both like-terms on the left side

$\sqrt{400}=\sqrt{c^2}$ --> Square-rooting both sides

$20=c$ --> Simplifying the radicals (square roots)

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$c=20$ is the answer!