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mylen [45]
3 years ago
8

X/5 + 1 = 7 x = 40 x = 5 x = 30 x = 35

Mathematics
2 answers:
masha68 [24]3 years ago
7 0
X/5 + 1 = 7

x = ?

x/5 = 7-1

x/5 = 6

x = 5( 6 )

x = 30 ✔️
lapo4ka [179]3 years ago
3 0

Answer:

x = 30

Step-by-step explanation:

x/5 + 1 = 7

subtract 1 from each side

x/5 + 1-1 = 7-1

x/5 = 6

Multiply each side by 5

x/5 *5 = 6*5

x = 30

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The probability is 2/5 that a $20 bill will be drawn from the wallet.

Step-by-step explanation:

There are 20 total bills in the wallet (5 $5, 7 $10, and 8 $20, 5+7+8=20). So if the finder and returner of the wallet was to be given one of the bills drawn from the wallet there would be an 8/20 chance the owner of the wallet would pull a 20. That's because there are 20 total bills in the wallet and 8 of them are $20.  

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Hope this helps!

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When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

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We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
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<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
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Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
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