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Olenka [21]
2 years ago
12

Complete the table. Thank you

Mathematics
2 answers:
lesya692 [45]2 years ago
7 0

Answer:

16.5

Step-by-step explanation:

The relationship between x and y is that y is just x+3.5. So if x is 13, then y is 13+3.5 which is 16.5.

Ghella [55]2 years ago
4 0
<h2>ANSWER</h2>

  • 16.5

<h2>SOLUTION</h2>

13+3.5=16.5

<em><u>IM</u></em><em><u> </u></em><em><u>FILIPINO</u></em>

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Can you please help me with this problem.
Nimfa-mama [501]

Answer:

C

Step-by-step explanation:

Calculator did it lol

5 0
3 years ago
Ima need help on this one pls do quick
pshichka [43]

Answer:

65

Step-by-step explanation:

The area of the square is 5^2=25 and the area of a single triangle is \frac{1}{2}(5)(4)=10.

The total area is the square plus the 4 triangles 25+4(10)=65

4 0
2 years ago
For each problem, select the answer from the two choices.
Veseljchak [2.6K]

Answer:

  1. a. More than 20
  2. b. Less than 10
  3. b. Less than 0.2

Step-by-step explanation:

  1. 212.5
  2. 9.7
  3. 0.1608

Hope it helped you

7 0
3 years ago
UULUT
NARA [144]

Answer:

The first error she made in computing the variance was to have placed -1,024 instead of +1,024

Step-by-step explanation:

we have the data set

87, 46, 90, 78, and 89

step 1

Find the mean

(87+46+90+78+89)/5

390/5=78

step 2

Subtract the Mean for each value of data set and square the result  and then adds the numbers

(87-78)^{2}+(46-78)^{2}+(90-78)^{2}+(78-78)^{2}+(89-78)^{2}

(9)^{2}+(-32)^{2}+(12)^{2}+(0)^{2}+(11)^{2}

81+1,024+144+0+121

so

The first error she made in computing the variance was to have placed -1,024 instead of +1,024

1,370

step 3

Work out the mean of those squared differences

1,370/5=274 ----> this value is called the "Variance"

4 0
4 years ago
How do I graph a parabola with a vertex at (3,6) with a y-intercept at 2
Aleonysh [2.5K]
To graph

graph the point (3,6)
yintercept is on the y axis so go up 2 units from the origin and plot the point (0,2)

now the parabola
we know it has to go through points (3,6) and (0,2)
therefor we now that it opens down
we also knwo that the vertex's y value is the axis of symmetry

so we also put a point at (6,2)
draw a parabola opening down through the points (0,2) (3,6)  (6,2), with (3,6) at the top/peak

see attachment

6 0
4 years ago
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