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Stolb23 [73]
4 years ago
12

8^x+3=16^x−1 solve the exponential equation ...?

Mathematics
1 answer:
Juli2301 [7.4K]4 years ago
6 0
Let us write down the equation clearly and in a proper manner. This will help in solving the equation very easily.

8^(x + 3) = 16^(x - 1)
(2^3)^(x + 3) = (2^4)^(x - 1)
(2)^3(x + 3) = (2)^4(x - 1)
Then
3(x + 3) = 4(x - 1)
3x + 9 = 4x - 4
4x - 3x = 9 + 4
x = 13

I hope the procedure is clear enough for you to understand. I also hope that this is the answer that has actually come to your desired help.
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Write a function rule for the table.
Anvisha [2.4K]
The correct answer is:  [D]:   " p = 7.50 h " .
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The pay, "p" , is a function of the hours worked.

When h = 2,  (h = number of hours);  

         the pay, "p" ,  is equal to " 7.50 * 2 "  = 15.00 dollars" ; as shown on table.

When h  = 4  ;  p = " 7.50 * 4 = 30.00 dollars" ; as shown on table .

When h = 6 ; p = " 7.50 * 6 = 45.00 dollars" ; as shown on table.

When h = 8 ; p = " 7.50 * 8 = 60.00 dollars" ; as shown on table. 
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3 years ago
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irga5000 [103]
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Add.
gayaneshka [121]

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8 7/24 hope this helps

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

Given:  The model of population of a certain city between the years 1965 and 1995 by the radical function

P(x)=75000\sqrt[3]{x-1940}

To find the x year at which population is 245,000, put this in equation we get

245000=75000\sqrt[3]{x-1940}\\\\\Rightarrow\frac{245000}{17000}=\sqrt[3]{x-1940}\\\\\Rightarrow3.266=\sqrt[3]{x-1940}\\\\\Rightarrow\ x-1940=(3.266)^3..........\text{[by taking cube on both sides]}\\\\\Rightarrow\ x-1940=34.8587\\\\\Rightarrow\ x=1940+34.8587\\\\\Rightarrow\ x=1974.8587\approx1975

Hence, at year 1975 the population of the city is 245,000.

5 0
3 years ago
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