How to write -1/2x + y=4 in slope form

An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a d

Andreyy89

The sum is greater than 6

4 0

2 years ago

Pablo, Sofia, and Mia got some candy eggs at a party. Pablo had three times as many eggs as Sofia, and Sofia had twice as many e

andrezito [222]

Pablo : 3(2x) = 6x
Sofia : 2x
Mia : x

Assuming x = 10
Mia : x = 10
Sofia : 2x = 2(10) = 20
Pablo : 3(2x) = 3(20) = 60

10 + 20 + 60 = 90
90/3 = 30 candy eggs per person

Pablo: 60 x 1/2 = 30
Sophia: 30-20 = 10 : 10
Mia : 30 - 10 = 20 : 20

Ratio of eggs given to sophia from pablo's set = 10/60 = 1/6
Ratio of eggs given to mia from pablo's set = 20/60 = 2/6 = 1/3

8 0

3 years ago

Daniel buys two apples for every five oranges. If you bought 12 apples, how many oranges dis he buy?

wariber [46]

Answer:

30 oranges

Step-by-step explanation:

2 apples : 5 oranges

12 apples : 30 oranges

because 12 apples is 6 times the original ratio, so we multiply the 5 oranges by 6 too.

8 0

3 years ago

Generate the nest three terms of each arithmetic sequence shown below.

o-na [289]

Answer:

A)2,6,10

B)2,-6,-18

C)-1,-3,-5

Step-by-step explanation:

A)a1=-2 and d=4

We know that the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{2}=a_{1}+(2-1)d$

$a_{2}=a_{1}+(1)d$

Substituting the given value we get

$a_{2}= -2+(1)4$

$a_{2}= -2+4$

$a_{2}= 2$

------------------------------------------

Similarly

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the given value we get

$a_{3}= -2+(2)4$

$a_{3}= -2+8$

$a_{3}= 6$

-------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the given value we get

$a_{4}= -2+(3)4$

$a_{4}= -2+16$

$a_{4}= 10$

-------------------------------------------------------------------------------------------

B $a_n=a_{(n-1)}-8$ with $a_1=10$

$a_2=a_{(2-1)}-8$

$a_2=a_{1}-8$

Substituting the given value

$a_2= 10-8$

$a_2=2$

---------------------------------------------------------------------

$a_3=a_{(3-1)}-8$

$a_3=a_{2}-8$

Substituting the value

$a_3=2-8$

$a_3= -6$

---------------------------------------------------------------------

$a_4=a_{(4-1)}-8$

$a_4=a_{3}-8$

Substituting the value

$a_4= -6-8$

$a_4= -14$

-------------------------------------------------------------------------------------------

C) $a_1=3, a_2=1$

Here the difference is -2

the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the value we get

$a_{3}= 3+(2)-2$

$a_{3}= 3-4$

$a_{3}= -1$

------------------------------------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the value we get

$a_{4}= 3+(3)-2$

$a_{4}= 3-6$

$a_{4}= -3$

----------------------------------------------------------------------------------

$a_{5}=a_{1}+(5-1)d$

$a_{5}=a_{1}+(4)d$

Substituting the value we get

$a_{5}= 3+(4)-2$

$a_{5}= 3-8$

$a_{5}= -5$

4 0

3 years ago

Joe collected 94 stamps altogether. He collected 27 in April and 34 in May. How many did he collect in June?

stepan [7]

Answer:

33

Step-by-step explanation:

From what we know in April and May combined Joe has collected 61 stamps (27+34=61). To then work out how many Joe collected in June you would take the 61 we know he has already got away from the grand total of 94 (94-61=33) this means in June he collects 33 stamps. Hope this helps :)

8 0

2 years ago