Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
(2)
Step-by-step explanation:
slope:-1/2
y-intercept:1 (because the function passes (0,1))
Hi Jessica,
<span>Remember PEMDAS (Parenthesis, Exponents, Multiplication & Division, Addition & Subtraction).
√3 x 66.15/4.41 {Exponents/Cube & Square Roots First}
1.73 x 66.15 ÷ 4.41 {Multiplication}
114.4395 ÷ 4.41 {Division}
25.95 {Final Answer}
Cheers,
Izzy</span>
If you are trying to create a garden of potted plants, you would find out how much soil each pot needs/holds and multiply that by how many pots you plan to use. then you would go to the store for potting soil, which let’s say came in smaller packs and you need to purchase multiple. use multiplication estimation to estimate how many bags you’d need.
I know this is a dumb example...sorry this is one I remember from my fourth grade math teacher ahah
G(x)=2x+3
x <span>≥ 1
g(x)=5
x is bigger then 1
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