<h3>The first time when the ball will reach a height of 20 feet is 0.42 seconds</h3>
<em><u>Solution:</u></em>
Given that,
<em><u>The height of a ball thrown into the air after t seconds have elapsed is:</u></em>

<em><u>What is the first time, t, when the ball will reach a height of 20 feet?</u></em>
Substitute h = 20

<em><u>Solve by quadractic formula</u></em>




Rounding off we get,
t = 2.08 , t = 0.42
Thus the first time when the ball will reach a height of 20 feet is 0.42 seconds
Answer:
segment XY = 6
segment XW = 5
segment WZ = 4
segment ZY = 5
6 + 5 + 4 + 5 = 20 units :))))
Answer:
- <u>$45</u> (with the assumption made below)
Step-by-step explanation:
The equation is garbled; thus, to explain you I will assume the equation is
Where:
- R(s) is the revenue in dollars, as a function of the number of seats occupied.
- s is the variable that represents the number of seast occupied
- 14 is the rate of change of the revenue per seat occupied (the price of a ticket).
- -325 is the fixed cost of the theater for a performance (the amount of money the theater will lose if none seat is occupied).
Thus, you can predict the revenue when 70 seats are occupied by substituting s with 70.
- R(70) = -325 + 980 = $655
The <em>residual value</em> from a prediction is equal to the real value (observed value) less the preducted value:
- Residual = real revenue - predicted revenue
- Residual = $700 - $655 = $45
Answer:
653.12 ft²
Step-by-step explanation:
2πrh + 2πr²
2(3.14)(8)(5) + 2(3.14)(8)²
251.2 + ²401.92 = 653.12