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andre [41]
3 years ago
15

A rectangular region is removed from another rectangular region to create the shaded region shown below. Find the area of the sh

aded region.

Mathematics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

57m^2

Step-by-step explanation:

First we need to find the area of both shaded and not shaded regions. Since we are solving area for 2-D images we will use the equation Area=length(with)

Shaded Region: 11(9)=99

Unshaded Region: 8(6)=42

Now we subtract the shaded region with the unshaded region to get an area of 57 Meters. Therefore the area of the shaded region is 57m^2

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Mars2501 [29]
\frac{5}{k}+\frac{k+3}{k+5}=\frac{5(k+5)}{k(k+5)}+\frac{k(k+3)}{k(k+5)}=\frac{5k+25+k^2+3k}{k(k+5)}=\frac{k^2+8k+25}{k(k+5)}\\\\Answer:E
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4 years ago
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9. What’s the answer to this please
Lady bird [3.3K]
<h2>Answer:</h2><h3>W = 5</h3><h3>Step-by-step explanation:</h3><h3>Simplify the brackets. </h3><h3>-2x^2 + wx - 4 - x^2 - 5x - 6 = -3x^2 - 10</h3><h3>Then simplify (-2x^2 + wx - 4 - x^2 - 5x - 6) to </h3><h3>( -3x^2 + wx - 10 - 5x)</h3><h3>This will give you 3x^2 + wx - 10 - 5x = -3x^2 - 10. </h3><h3>Now you need to cancel out -3x^2 on both sides. </h3><h3>wx - 10 - 5x = -10</h3><h3>Then cancel out -10 from both sides. </h3><h3>wx - 5x = 0</h3><h3>Now factor out the common term. (x) </h3><h3>w - 5 = 0.</h3><h3>giving you the answer w = 5. </h3><h3 /><h3 /><h3>welcome. *yeets*</h3>
6 0
3 years ago
Find the ordered pair whose x-coordinate is 5. 4x=6y+8
sukhopar [10]

(6, 2 )

substitute x = 5 into the equation and solve for y

6y + 8 = 20 ( subtract 8 from both sides )

6y = 12 ( divide both sides by 6 )

y = \frac{12}{6} = 2

the ordered pair is (5, 2 )


6 0
3 years ago
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Find the equation of the line using the point-slope formula. Write the final equation using slope-intercept form. (1,2) with a s
Lilit [14]

Answer:

y-2=\displaystyle -\frac{3}{4}(x-1)

OR

y=\displaystyle -\frac{3}{4}x+\frac{11}{4}

Step-by-step explanation:

Hi there!

Point-slope form: y-y_1=m(x-x_1) where <em>m</em> is the slope of the line and (x_1,y_1) is a given point

Given that the slope is -3/4, we can plug it into y-y_1=m(x-x_1) as <em>m</em>:

y-y_1=\displaystyle -\frac{3}{4}(x-x_1)

We can also plug in the given point (1,2):

y-2=\displaystyle -\frac{3}{4}(x-1)

Slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when the line crosses the y-axis)

To write the equation in slope-intercept form, isolate <em>y</em>:

y-2=\displaystyle -\frac{3}{4}(x-1)\\\\y=\displaystyle -\frac{3}{4}(x-1)+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{3}{4}+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{11}{4}

I hope this helps!

8 0
2 years ago
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Answer:

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Therefore 46 = -3 + 5d

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They are:

6.8, 16.6, 26.4, 36.2.

3 0
3 years ago
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