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Yuki888 [10]
2 years ago
9

The length of a rectangular house is two and a half times its width. Solve the problem using x to denote the shorter side of the

rectangle.
a) construct the expression for the area or the rectangle in terms of x

b) calculate the area if x=32 feet
Mathematics
2 answers:
Pavlova-9 [17]2 years ago
4 0

answer

a.) y=2.5x

area=2.5x^2

b.)2560

Step-by-step explanation:

denpristay [2]2 years ago
3 0

a.  The construct the expression for the area of the rectangle in terms of x is y=2.5x

b. The area should be 2,560.

Given that,

  • the length of a rectangular house is two and a half times its width.

Based on the above information, the calculation is as follows:

a) The expression should be y = 2.5x

b) The area should be

=2.5x^2\\\\= 2.5(32)^2  

= 2560

Learn more: brainly.com/question/1301963?referrer=searchResults

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Answer:

x = -10, x=5

Step-by-step explanation:

x^2 +5x - 50 = 0

What two number multiply to -50 and add to 5

10 * -5 = -50

10 + -5 = 5

( x+10) (x-5) =0

Using the zero product property

x+10 =0    x-5 =0

x+10-10 =0-10   x-5+5=0+5

x= -10                 x =5

4 0
3 years ago
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vladimir1956 [14]
For the second half,

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3 years ago
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Vlada [557]

Answer:

750

Step-by-step explanation:

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7 0
3 years ago
Three cards are drawn with replacement from a standard deck. What is the probability that the first card will be a diamond, the
noname [10]

Answer:

The probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen is 0.0096

Step-by-step explanation:

Total no. of cards = 52

No. of diamond cards = 13

No. of black cards = 26

No. of queens = 4

Three cards are drawn with replacement from a standard deck.

We are supposed to find he probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen

Probability of getting diamond card =\frac{13}{52}

Probability of getting black card =\frac{26}{52}

Probability of queen =\frac{4}{52}

Probability  that the first card will be a diamond, the second card will be a black card, and the third card will be a queen =\frac{13}{52} \times \frac{26}{52} \times \frac{4}{52}=0.0096

Hence the probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen is 0.0096

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4 years ago
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-P
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