I think the answer maybe will be 3)5 and the reason why Is because
Answer:
The answer is D
Step-by-step explanation:
the only one that makes sense
the final speed in m/s of the 10.0 kg is 2.53 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:
We know that in an elastic collision :
⇒ Total kinetic energy before collision = Total kinetic energy after collision
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .
So it is given that f(x) and g(x) are inverse of each other.
Then f(5) = -7 and hence g(-7) = 5
Now let's use f( g( x ) ) = x
Now take deviation. Use chain rule:
f'( g(x) ) g'( x ) = 1
Plug in x = -7
f'( g( -7 ) ) g'( -7 ) = 1
f'( g( -7 ) ) · -2/3 = 1
f'( g( -7 ) ) = -3/2
f'( 5 ) = -3/2
Hope this helps.
Answer:
Answer in the picture: x = 1 | y = -5
Step-by-step explanation:
Not sure if that's the answer you're looking for but I think that's it