It helps you because it makes it easier to divide you just have to keep using place value to find the quitent
I'm assuming you mean
![\frac{x^3+y^3}{x-y}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E3%2By%5E3%7D%7Bx-y%7D)
we can factor that sum of perfect cubes from
![x^2+y^3](https://tex.z-dn.net/?f=x%5E2%2By%5E3)
into
![(x+y)(x^2-xy+y^2)](https://tex.z-dn.net/?f=%28x%2By%29%28x%5E2-xy%2By%5E2%29)
so therefor
![\frac{x^3+y^3}{x-y}=\frac{(x+y)(x^2-xy+y^2)}{x-y}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E3%2By%5E3%7D%7Bx-y%7D%3D%5Cfrac%7B%28x%2By%29%28x%5E2-xy%2By%5E2%29%7D%7Bx-y%7D)
that is simpliest form
Answer:
1)4
2)28
3)18.3
4)38.5
5)22.5
6)19.25
7)25.5
8)69.666
9)6.5
10)22.666
Step-by-step explanation:
- To do this first you should convert the mix numbers into inproper fractions and then solve.
1)8/5*5/2=4
2)21/5*20/3=7*4
=28
3)33/4*20/9=11*5/3
=55/3
=18.33...
=18.3
4)35/6*33/5=7*11/2
=77/2
=38.5
5)22/8*90/11=45/2
=22.5
6)11/3*21/4=11*7/4
=77/4
=19.25
7)34/5*15/4=34*3/4
=25.5
8)22/3*57/6=11*19/3
=209/3
=69.666
9)39/8*4/3=13/2
=6.5
10)17/2*8/3=17*4/3
=68/3
=22.666
<em>Hope you got this</em>
<em>If you have any doubt please ask me</em>
<em>If you need this in fraction form just check the attachment</em>
Answer:
37.5
Step-by-step explanation:
180-75 = 105
180 is the sum of all the angle in a triangle
180-105 = 75
75/2 = x becuz the triangle is icoceles
=37/5
Hope this helps :) Giving me brainiest would help a lot :))