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Brrunno [24]
3 years ago
14

Simplify 7-[x - (-2x + 9)]. –x - 2 -3x + 16 3x - 2

Mathematics
1 answer:
mylen [45]3 years ago
6 0
- 2x(x^2 - 3)
=(- 2x)(x2) + (- 2x)(- 3)
= - 2x3 + 6x

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How can you use the properties of operations to evaluate<br> this expression?<br> 18 + 4(28)
pentagon [3]

Answer:

first open the bracket by multiplying 28 by 4 which is equal to 112, then add it to 18 which be equal to 130 which is the final answer

5 0
3 years ago
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A department store buys 300 shirts for a total cost of 7,200 and sells them for $30 each. Find the percent markup.
worty [1.4K]

Step-by-step explanation:

7200 ÷ 300 = 24

30 - 24 = 6

6/24 × 100/1 = 25%

3 0
3 years ago
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Please answer correctly! I will mark you as Brainliest!
alukav5142 [94]

Answer:

1024pi/3

Step-by-step explanation:

to find the volume of a sphere you use the equation 4/3*pi*r^3

4/3*pi*8^3

4/3*pi*512

2048/3 pi

This is the volume of the whole sphere but we only need half so we can just divide by 2.

(2048/3 pi)/2

1024/3 pi

6 0
3 years ago
Find the mode of the following data . 12,8,4,8,1,8,9,11,9,10,12,8​
Y_Kistochka [10]

Answer:

8

Step-by-step explanation:

The mode of a set of data values is the value that appears most often

7 0
3 years ago
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The Great Pyramid in Giza, Egypt, is a square pyramid. The dimensions of the pyramid at the time of its completion are shown in
ryzh [129]

Answer:

Area of square pyramid is 153883.8\ m^{2}.

Step-by-step explanation:

Diagram of the given scenario is shown below,

Given that,

The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is 154 \ m^{2}. The side of the square is 230 \ m and The height of each triangle is 187 \ m.

So,    Area of Square shape  = 154 \ m^{2}

         Side of square = 230 \ m

      Height of each triangle = 187 \ m

Finding the Height of triangular shape which is here known as slant height.

 In Δ ABO, applying Right angle pythagorean Theorem,

                  Base (BO) =  \frac{230}{2} = 115\ m

                Height (AO) = 187\ m

Now,      

∴                   AB^{2} = AO^{2} \ + \ BO^{2}

⇒                    AB= \sqrt{AO^{2} \ + \ BO^{2}  }

⇒                   AB= \sqrt{187^{2} \ + \ 115^{2}  }

⇒                   AB= \sqrt{34969 \ + \ 13225   }

⇒                   AB= 219.53 \ m

Then,

           Area of square pyramid = area \ of \ square + \ 4\times area \ of \ traiangle

                                                   = side\times side + 4\times\frac{1}{2}\times AB\times Base  

                                                   = 230\times 230 \  + 2\times 219.53\times 230

                                                   = 52900 + 100983.8

                                                   = 153883.8 \ m^{2}

Hence, Area of square pyramid is 153883.8\ m^{2}.

                   

6 0
3 years ago
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