A) approx = 1-8x
b) f(x) -8(1-x)^-1 approx = -8(1+x) = -8 - 8x
because 1/x = x^-1...
c) f(x) = (1+x)^-1/2 approx = 1- 1/2x
d) f(x) = (4+x^2)^1/2 approx = 4 + 1/2x^2
e) f(x) = (6+3x)^1/3 approx = 6+x
322,000 meters per hour...Good Luck! God bless
Given:

To find:
Draw a graph of a line that is perpendicular to the given line and passing through a given point.
Explanation:
As we know that relation between two slopes of perpendicular slopes of lines:

Slope of given line y = 4x + 1 is:

So, the slope of line perpendicular to given line is:

Also, so line equation that is perpendicular to given line is:

Also, the required line is passing thorugh given point (2, 3), i.e.,

So, line equation that is perpendicular to given line is:

The required graph of line is:
Answer:
.
Step-by-step explanation:
Start by finding the slope of the line perpendicular to
.
The slope of
is
.
In a plane, if two lines are perpendicular to one another, the product of their slopes would be
.
Let
denote the slope of the line perpendicular to
. The expression
would denote the product of the slopes of these two lines.
Since these two lines are perpendicular to one another,
. Solve for
:
.
The
is a point on the requested line. (That is,
and
.) The slope of that line is found to be
. The equation of that line in the point-slope form would be:
.
Rewrite this point-slope form equation into the slope-intercept form:
.