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aniked [119]
2 years ago
10

EASY MATH QUESTION pls help asap

Mathematics
1 answer:
zhuklara [117]2 years ago
7 0

Answer:

b 16 adult is - 40 people end of day

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Aflati un numar stiind ca 1/3 din 1/1/3 din el este 40 VA ROG MULT DAU COROANA
I am Lyosha [343]

Answer:

This is such a unique language. What language is this? I wanna try and learn it

6 0
3 years ago
A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed
zubka84 [21]
<span>55832 + 11.25 x = 25.25 x

</span>55832 = 14 x

x = 3988 books


4 0
3 years ago
Find the total capacity of 50 containers of orange juice if container holds 1 gallon 2 quarts 1 pint.
Scorpion4ik [409]
I think its 81 gallons 1 quart

7 0
4 years ago
Read 2 more answers
Solve by graphing <br><br> u=v and 6u=2v-24
Vadim26 [7]

Answer:

u=-6 \\ \\ v=-6

Step-by-step explanation:

In this exercise, we have two equations, namely:

u=v \ and \ 6u=2v-24

And we are asked to solve this problem by graphing. In this way, we can write a system of linear equations in two variables, but first of all, let's rewrite:

u=y \\ \\ v=x

Then:

\left\{ \begin{array}{c}y=x\\6y=2x-24\end{array}\right.

So here we have two lines.

The first one is:

\boxed{y=x}

This line passes through the origin and has a slope m=1

The second one is:

6y=2x-24 \\ \\ \therefore y=\frac{2x-24}{6} \\ \\ \therefore \boxed{y=\frac{1}{3}x-4}

This line has a slope m=\frac{1}{3} and cuts the y-axis at b=-4

By using graph tools, we get the graph shown below, then:

x=-6 \\ \\ y=-6 \\ \\ \\ Since \ u=y \ and \ v=x, then: \\ \\ u=-6 \\ \\ v=-6

8 0
3 years ago
If Acot theta + Bcot theta =4 and
geniusboy [140]

Answer is: B

Step-by-step explanation: correct answer is B

b  

2

−a  

2

 

Given, acotθ+bcscθ=p

           bcotθ+acscθ=q

⇒p  

2

−q  

2

=(p−q)(p+q)

                   =[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]

                   =[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]

                   =(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)

                   =(a  

2

−b  

2

)(cot  

2

θ−csc  

2

θ)

                   =(−1)(a  

2

−b  

2

)[∵csc  

2

θ−cot  

2

θ=1]

                   =(b  

2

−a  

2

)

7 0
3 years ago
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