The term commonly used in accounting to describe the format for recording a transaction is:.

Which element is the basis for all living things and can combine with other elements in many ways? phosphorus carbon oxygen sulf

Lisa [10]

The answer is carbon

5 0

3 years ago

Read 2 more answers

a pie is cut so that one piece, which is one quarter of the pie, is twice as large as each of the other pieces. into how many pi

ANTONII [103]

Answer:7

Explanation: pie

5 0

3 years ago

Please help me as soon as possible!

Lena [83]

If you add it it'll become -3x^2+5x+7

6 0

3 years ago

What is the product? mc019-1. Jpg mc019-2. Jpg mc019-3. Jpg mc019-4. Jpg.

Ede4ka [16]

Answer:

C

Explanation:

(-2x-9y^2)(-4x-3)

Distributing -2x:

-2x * -4x = 8x^2

-2x * -3 = 6x

Distributing -9y^2:

-9y^2 * -4x = 36xy^2

-9y^2 * -3 = 27y^2

8x^2+6x +36xy^2 + 27y^2

I asked the same question and got this as an answer. Hope this helps! :)

5 0

2 years ago

Once you have your heap structure created, next you must use it as a backing structure to a priority queue. Develop a PriorityQu

saveliy_v [14]

Using the knowledge in computational language in python it is possible to write a code that Develop a PriorityQueue data structure in a file.

<h3>Writting the code in python:</h3>

import sys

class Node:

def __init__(self,key):

self.left = None

self.right = None

self.val = key

self.parent = None

class MinHeap:

def __init__(self, maxsize):

self.maxsize = maxsize

self.size = 0

self.Heap = Node(-1 * sys.maxsize )

self.FRONT = self.Heap

# A utility function to do inorder tree traversal

def isLeaf(self, node):

if node.left == None and node.right == Node:

return True

return False

# Function to swap two nodes of the heap

def swap(self, node1, node2):

node1.data, node2.data = node2.data, node1.data

# Function to heapify the node at pos

def minHeapify(self, node):

# If the node is a non-leaf node and greater

# than any of its child

if not self.isLeaf(node):

if (node.data > node.left.data or

node.data > node.right.data):

# Swap with the left child and heapify

# the left child

if node.left.data < node.right.data:

self.swap(node, node.left)

self.minHeapify(node.left)

# Swap with the right child and heapify

# the right child

else:

self.swap(node, node.right)

self.minHeapify(node.right)

# Function to insert a node into the heap

def insert(self, element):

if self.size >= self.maxsize :

return

self.size+= 1

self.bst_insert(FRONT, element)

current = FRONT

while current.parent != None and current.data < current.parent.data:

self.swap(current, current.parent)

current = current.parent

# Function to print the contents of the heap

def Print(self):

self.inorder()

# Function to build the min heap using

# the minHeapify function

def inorder(self, root):

if root:

inorder(root.left)

print(root.val)

inorder(root.right)

def bst_insert(self, root, node):

if root is None:

root = node

else:

root.next = node

self.FRONT = node

# Driver Code

if __name__ == "__main__":

r = Node(50)

bst_insert(r,Node(30))

bst_insert(r,Node(20))

bst_insert(r,Node(40))

bst_insert(r,Node(70))

bst_insert(r,Node(60))

bst_insert(r,Node(80))

# Print inoder traversal of the BST

inorder(r)

print('The minHeap is ')

minHeap = MinHeap(15)

minHeap.insert(5)

minHeap.insert(3)

minHeap.insert(17)

minHeap.insert(10)

minHeap.insert(84)

minHeap.insert(19)

minHeap.insert(6)

minHeap.insert(22)

minHeap.insert(9)

minHeap.minHeap()

minHeap.Print()

print("The Min val is " + str(minHeap.remove()))

See more about python at brainly.com/question/13437928

#SPJ1

6 0

1 year ago