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Anestetic [448]
2 years ago
15

What is the quotient (91y3 + 21y2 − 35y) ÷ 7y?

Mathematics
1 answer:
VLD [36.1K]2 years ago
3 0

answer:13yexponent2+3y−5

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Geometry hw! Pls help!
natima [27]

Answer:

C

Step-by-step explanation:

1. Identfiy The type therom it is which is alternate interior

2. Find the converse of the alternate interior which is the oppoiste so it has to be alternate exterior angle

6 0
3 years ago
You are buying pizzas for a neighborhood party. Each pizza costs $9 and you want to tip the delivery guy $5. You have $72.
TiliK225 [7]

Answer:

7 pizzas

Step-by-step explanation:

You just minus 72 from 9 and once you get to 9 dollars you still have enough to time the delivery guy and you would have 4 dollars left.

3 0
2 years ago
Read 2 more answers
Is the relation a function? {(14, 15), (5, 7), (3, 10), (11, 1), (5, 8)} a. yes. b. no
Monica [59]
In this relation we have two ordered pairs:
( 5, 7 ) and ( 5, 8 )
For x = 5 :  f ( x ) = 7 and also for x = 5,  f ( x ) = 8. This is not possible for a function.
Answer:
b ) No. The relation is not a function.
8 0
3 years ago
Mrs. Totino makes her own spaghetti sauce. If she buys 24 cans of tomatoes, and
PilotLPTM [1.2K]

Well, this is easy and rather basic in my opinion. If you open a calculator and multiply 79.924 by 24, you come out with 1,902.96 grams. If you wanted to convert it into pounds, it would be 4 pounds.

7 0
2 years ago
Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda
pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

Step-by-step explanation:

Given equation is

x^2y'' - 9xy+24y=0

This Euler Cauchy type differential equation.

So, we can let

y=x^m

Differentiate with respect to x

y'= mx^{m-1}

Again differentiate with respect to x

y''= m(m-1)x^{m-2}

Putting the value of y, y' and y'' in the differential equation

x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0

\Rightarrow m(m-1)x^m-9mx^m+24x^m=0

\Rightarrow m^2-m-9m+24=0

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

⇒(m-6)(m-4)=0

⇒m = 6,4

Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

y_1(x)=x^4

and

y_2(x)=x^6

First we compute the Wronskian

W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|

         = \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|

         =x⁴×6x⁵- x⁶×4x³    

        =6x⁹-4x⁹

        =2x⁹

       ≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

5 0
3 years ago
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