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Jobisdone [24]
2 years ago
10

What is an equation in point-slope form of the line that passes through (−1,−4) and (2, 5)?

Mathematics
2 answers:
vitfil [10]2 years ago
7 0
The answer is y+4=3(x+1) C
lakkis [162]2 years ago
5 0

Answer:

I think y−4=3(x−1)

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PLEASE HELP THIS IS DUE TODAY AND I HAVE NO IDEA WHAT THE ANSWER IS!!!!!!
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3 years ago
salesman Scott received $2,792.79 for selling a property. If the gross commission was 6 1/2 % of the sale price, the listing sal
larisa [96]

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Sorry! Just doing this for points!

Step-by-step explanation:

6 0
3 years ago
Find the mean.<br> Z-score = -1.4<br> Standard Deviation: 7<br> x = 20
Umnica [9.8K]

Answer:

9.6

Step-by-step explanation:

8 0
3 years ago
A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.
melisa1 [442]
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°. 

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

\overline{OB}:\overline{AB} = 1:2
\overline {OB}:10 = 1:2
\overline{OB} = \frac{1}{2}(10) = 5

Similarly, we have

\overline{AO}:\overline{AB} = \sqrt{3}:2
\overline {AO}:10 = \sqrt{3}:2
\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}

Now, to find the lengths of the diagonals, 

\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}
\overline{BC} = 2(\overline{OB}) = 10

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units

8 0
3 years ago
Consider the points.
miskamm [114]

Answer:

6 units

Step-by-step explanation:

Use the distance formula, \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

Plug the x and y values from the given points into the distance formula:

\sqrt{([-4]-2)^{2}+(5-5)^{2}}.

Solve the square root:

\sqrt{36} = \sqrt{6^{2}} = 6

3 0
3 years ago
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