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3 years ago

5

An Astronaut drops a rock into crater on the moon. The distance,d(t), in meters, the rock travels after t seconds can be modeled

by the function d(t) = 0.8t. What is the average speed,in meters, per second,of the rock between 5 and 10 seconds after it was dropped?

1 answer:

OlgaM077 [116]3 years ago

4 0

speed =distance traveled over time taveled... the ansewr will be in kilometres per hour

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40cm²

Step-by-step explanation:

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Anyone have the answer for this

sergiy2304 [10]

$\huge\bold{Given:}$

Length of the base = 16 km.

Length of the hypotenuse = 34 km. $\huge\bold{To\:find:}$

✎ The length of the missing leg '' $a$ ".

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

The length of the missing leg "a" is $\boxed{30\:km}$ .

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

Using Pythagoras theorem, we have

$({perpendicular})^{2} + ({base})^{2} = ({hypotenuse})^{2} \\ ⇢ {a}^{2} + ({16 \: km})^{2} = ({34 \: km})^{2} \\ ⇢ {a}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇢ {a}^{2} = 1156 \: {km}^{2} - 256 \: {km}^{2} \\ ⇢ {a}^{2} = 900 \: {km}^{2} \\ ⇢a \: = \sqrt{900 \: {km}^{2} } \\ ⇢a = \sqrt{30 \times 30 \: {km}^{2} } \\ ⇢a = 30 \: km$

$\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}$

$\huge\bold{To\:verify :}$

$( {30 \: km})^{2} + ({16 \: km})^{2} =( {34 \: km})^{2} \\ ⇝900 \: {km}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\⇝1156 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇝L.H.S.=R. H. S$

Hence verified. ✔

$\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘$

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2 years ago

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Ne4ueva [31]

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Step-by-step explanation:

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3 years ago

2 3/4+3 5/8 simplified

otez555 [7]

$2\frac{3}{4}+3 \frac{5}{8}=6\frac{3}{8}$

Solution:

Given expression is $2\frac{3}{4}+3 \frac{5}{8}$ .

To simplify the expression $2\frac{3}{4}+3 \frac{5}{8}.$

Let us first convert the mixed fraction into improper fraction.

$2\frac{3}{4}+3 \frac{5}{8}=\frac{(2\times 4) + 3}{4}+ \frac{(3 \times 8)+5}{8}$

$=\frac{8+ 3}{4}+ \frac{24+5}{8}$

$=\frac{11}{4}+ \frac{29}{8}$

Take LCM for the denominators (LCM of 4, 8 = 8) and make the same.

$=\frac{11\times2}{4\times 2}+ \frac{29\times1}{8\times1}$

$=\frac{22}{8}+ \frac{29}{8}$

$=\frac{51}{8}$

Now, divide 51 by 8 and again write it in the mixed fraction.

$=6\frac{3}{8}$

$2\frac{3}{4}+3 \frac{5}{8}=6\frac{3}{8}$

Hence, the simplified answer is $6\frac{3}{8}$ .

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