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2 years ago

125 divided by 100 I have to make corrections

Mathematics

2 answers:

STatiana [176]2 years ago

5 0

Answer:

1.25

Step-by-step explanation:

125/100 = 1.25

Brrunno [24]2 years ago

4 0

Answer:

it's 1.25

Step-by-step explanation:

125 ÷100 = 1.25

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mamaluj [8]

Answer:

3.60

Step-by-step explanation:

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2 years ago

So it says change the following fractions and mixed numbers to decimal numbers

puteri [66]

Answer:

2.16666666667 or rounded to 2.17

Step-by-step explanation:

first you have to change the mixed number to an improper fraction which would be 13/6 and then divide the numerator by the denominator

6 0

2 years ago

Need help on 15 and 16 PLEASEE!!!

melisa1 [442]

Answer:

Part 15) The next three terms are 5/8,3/4 and 7/8

Part 16) The 37th term is -35.5

Step-by-step explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant and this constant is called the common difference (d)

Part 15) Find the next three terms of the arithmetic sequence

$\frac{1}{8},\frac{1}{4},\frac{3}{8},\frac{1}{2},...$

$a1=1/8\\ a2=1/4\\ a3=3/8\\ a4=1/2\\ a2-a1=1/4-1/8=1/8\\ a3-a2=3/8-1/4=1/8\\ a4=a3=1/2-3/8=1/8$

The common difference is equal to

d=1/8

Find the next three terms of the arithmetic sequence

Find a5

$a5=a4+d$ -----> $a5=1/2+1/8=5/8$

Find a6

$a6=a5+d$ -----> $a6=5/8+1/8=3/4$

Find a7

$a7=a6+d$ -----> $a7=3/4+1/8=7/8$

therefore

The next three terms are

5/8,3/4 and 7/8

Part 16) what is the 37th term of the arithmetic sequence

$4.1,3,1.9,0.8,...?$

$a1=4.1\\ a2=3\\ a3=1.9\\ a4=0.8$

$a2-a1=3-4.1=-1.1\\ a3-a2=1.9-3=-1.1\\ a4=a3=0.8-1.9=-1.1$

The common difference is equal to

d=-1.1

We can write an Arithmetic Sequence as a rule

$an=a1+d(n-1)$

substitute the values

$an=4.1-1.1(n-1)$

For n=37

substitute

$a37=4.1-1.1(37-1)$

$a37=4.1-1.1(36)$

$a37=-35.5$

4 0

2 years ago

-3 radical 2 times radical 3

topjm [15]

Answer:

-6

Step-by-step explanation:

$-3\sqrt{2}*\sqrt{2} = -3*2 = -6\\$

3 0

2 years ago

The quadratic function f(x) has a turning point at (-3,6). the quadratic y=2/3f(x)+3 would have a turning point of

NARA [144]

Answer:

C. (-3,11)

Step-by-step explanation:

Tp is (-3,6) implies the quadratic could have been

f(x) = (x+3)²+6

(2/3)f(x) = (2/3)[(x+3)²+6]

= (2/3)(x+3)²+4

(2/3)f(x)+3 = (2/3)(x+3)²+4+3

= (2/3)(x+3)²+7

Tp at (-3,7)

Alternately,

No change in domain so x remains-3

(2/3)f(x) changes y from 6 to 4 (6×2/3)

+3 increases the y by 3

i.e 4+3 = 7

So, (-3,7)

4 0

2 years ago