Answer:
The answer is C. Boning knife
The correct answer is C) labor-saving advances in households.
A study of labor force participation rates of women in the post-World War II period noted:
Over the long run, women have joined the paid labor force because of a series of changes affecting the nature of work. Primary among these was labor-saving advances in households.
This is an important factor because new inventions and technology have allowed women to leave the house in order to have an education an enter the job force in the corporate world because they have shown the be very capable to perform jobs in industries and companies, at the highest levels. Today, many families need a double income in the house in order to make a decent living. So it is common to see the father and the mother having a job.
Answer:
Momentous Occasions
a. Revenue of $1,000 is recognized on April 2, though the cash receipt is recorded on March 3 as deferred revenue. This means that the recognition occurred on a separate date from when the cash was received.
b. Revenue of $4,100 will be recognized on the date the party is held and not on the February 28 date when the cash was received. This means that the recognition occurred on a separate date from when the cash was received.
Explanation:
Momentous Occasions is required to recognize revenue on the date the service is performed and not when the cash is received in accordance with the accrual concept, unless it chooses to use the cash basis as a small business.
Answer:
Being on time in business situations generally means being about 5 minutes early
Explanation:
5 minutes late is acceptable with a brief apology. Ten to fifteen minutes late requires a phone call to warn of the delay and to apologize.
Answer:
Profit Maximising Quantity = 775
Explanation:
Price P = 35 - 0.02Q
Total Revenue TR = Price x Quantity = P X Q
= (35 - 0.02Q)(Q) = 35Q - 0.02Q^2
Total Cost TC = 8000 + 4Q
Profit = TR - TC
[35Q - 0.02Q^2] - [8000+4Q] = 35Q - 0.02Q^2 - 8000 - 4Q
Profit Function = - 0.02Q^2 + 31Q - 8000
To find out profit maximising Quantity , we will differentiate Profit Function with respect to Q & equate it to 0.
dTR/ dQ = -0.04Q + 31 = 0
Q = 31/0.04 = 775
To verify whether 775 is profit maximising Q, we will do second derivative & check that it is negative.
d^2TR/ dQ^2 = -0.04 i.e < 0 (negative)
So 775 is profit maximising quantity
