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pychu [463]
3 years ago
5

Write an equation of a line that

Mathematics
1 answer:
lord [1]3 years ago
4 0

Answer:

(3 times 2)+(9 times 6)

Step-by-step explanation:

The total will equal 60 but also the 6 and 3 represents the money so if u have to put the $ sign u can

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Write an algebraic expression for the verbal description. the sum of two consecutive natural numbers, the first of which is n
scoundrel [369]
I think it may be:

n + (n + 1)

hope this helps
8 0
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A saleswoman received $40
dangina [55]

you multiply the commission by her sales and get 25.20$ then add that to her bae pay of 280 a week and get 305.20$ as your answer.

4 0
3 years ago
10 pounds of onions cost $100 how many pounds of onions can get with $150
erma4kov [3.2K]

Answer:

15

Step-by-step explanation:

$100 / 10 pounds = $10 / pound

$150 / 10 dollars  = 15 pounds of onions

4 0
3 years ago
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(3 marks) A certain type of storage battery lasts, on average, 3.0 years with a standard deviation of 0.5 year. The battery live
Ksenya-84 [330]

Answer:

0.8041 = 80.41% probability that a given battery will last between 2.3 and 3.6 years

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A certain type of storage battery lasts, on average, 3.0 years with a standard deviation of 0.5 year

This means that \mu = 3, \sigma = 0.5

What is the probability that a given battery will last between 2.3 and 3.6 years?

This is the p-value of Z when X = 3.6 subtracted by the p-value of Z when X = 2.3. So

X = 3.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.6 - 3}{0.5}

Z = 1.2

Z = 1.2 has a p-value of 0.8849

X = 2.3

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.3 - 3}{0.5}

Z = -1.4

Z = -1.4 has a p-value of 0.0808

0.8849 - 0.0808 = 0.8041

0.8041 = 80.41% probability that a given battery will last between 2.3 and 3.6 years

4 0
3 years ago
Hello I need help on this question and for the second equation I’m not sure how I would graph that so could you maybe please hel
Alborosie

Answer:

Do you want me to solve it on a graph???

Step-by-step explanation:

3 0
2 years ago
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