Could anyone help me / giving crowns away

GCF of 30 48 and 72

USPshnik [31]

The greatest common factor of those numbers is 8.

7 0

3 years ago

Find the tangent of angle A (giving brainliest and thanks to all!)

Shtirlitz [24]

Answer:

Option B, 8 / 6

Step-by-step explanation:

Tangent = Opposite / Adjacent

Tangent of ∠A = Opposite / Adjacent

Tan(A) = 8 / 6 which is the same as Option B

Hope this helps!

3 0

3 years ago

What is the simplest form of the expression 6x(x − 4) − 16x2 − (9x − 1)

Sedbober [7]

Use distributie property which is
a(b+c)=ab+ac
therefor
6x(x-4)=6x^2-24x

distribute the negative 1 infroont of the (9x-1)
-1(9x-1)=-9x+1
now we have

6x^2-24x-16x^2-9x+1
gropu like terms
6x^2-16x^2-24x-9x+1
add like terms
-10x^2-33x+1 is simplest form

8 0

3 years ago

Monica has $20. She needs to buy a gallon of milk that costs $2.50. She also wants to buy yogurt, which costs $1.20 a cup. What

trapecia [35]

Answer: The greatest number of cups of yogurt MOnica can buy is 14.

Step-by-step explanation:

If she need to buy a gallon of milk then it means that $2.50 will be deducted from the money .

Use the the inequality to solve for how many cups of yogurt Monica can buy

1.20x + 2.50 ≤ 20

-2.50 2.50

1.20x ≤ 17.5

x≤14.5833...

which means the greatest number of cups of yogurt Monica can buy is 14.

8 0

2 years ago

John, Sally, and Natalie would all like to save some money. John decides that it would be best to save money in a jar in his clo

Radda [10]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) Is a exponential growth function

Part 5) $A=6,000(1.07)^{t}$

Part 6) $\$11,802.91$

Part 7) Is a exponential growth function

Part 8) $A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

Part 9) $\$13,591.41$

Part 10) Natalie has the most money after 10 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

$y=mx+b$

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

so

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

$y=100x+300$

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

10 years=10(12)=120 months

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\\ r=7\%=0.07\\n=1$

substitute in the formula above

$A=6,000(1+\frac{0.07}{1})^{1*t}$

$A=6,000(1.07)^{t}$

therefore

Is a exponential growth function

Part 5) Write the model equation for Sally’s situation

$A=6,000(1.07)^{t}$

see the Part 4)

Part 6) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{10}=\$11,802.91$

Part 7) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\\r=10\%=0.10$

substitute in the formula above

$A=5,000(e)^{0.10t}$

Applying property of exponents

$A=5,000(1.1052)^{t}$

therefore

Is a exponential growth function

Part 8) Write the model equation for Natalie’s situation

$A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

see Part 7)

Part 9) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^{0.10*10}=\$13,591.41$

Part 10) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

4 0

3 years ago

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