M<A + m<B = 180
5y + 9y + 68 = 180
14y + 68 = 180
14y = 180 -68
14y = 112
y = 112/14
y = 8
so
m<B = 9y + 68
m<B = 9(8) + 68
m<B = 72 + 68
m<B = 140
The answer is three significant figures. The 1 and the 7 are both significant, because they are non-zero quantities.
This is where significant figures gets a little more complicated, because if a zero is used as a placeholder (i.e. 0.00027 cm) then it is insignificant.
But in the case above, the zero isn't being used as a placeholder, and thus, is significant.
Answer:
I'm pretty sure its C sorry if I'm wrong.
let
x-------> workers in team one initially
y-------> workers in team two initially
we know that
x=2y-----> equation 1
(x-5)=(y-2)+7-----> x-5= y+5----> x=y+10---------> equation 2
equate equation 1 and equation 2
2y=y+10-----> y=10
x=2*10------> x=20
Team 1 now has 20-5 = 15 members Team 2 now hase 10-2 = 8 members
