Answer:
To find the mode you need to check the number which is more often repeated in the set than the other.But as you can see here there is no number which is repeated more often than the other everyone is repeated once,so in this case we say that the set of data values has no mode.
To find the the range of the set of data you need to first place the numbers in ascending order (as it is already in) and then find the greatest and the smallest number and subtract them.
Range :
10,20,30,40,50,60,70,80,90,100,110,120,130,140,150.
Greatest number = 150.
Smallest number = 10.
Subtract = 150-10 = 140.
Step-by-step explanation:
Using the formula for area of a circle:
Area = pi x radius^2
Replace area with the given value:
39.62 = pi x radius^2
Divide both sides by pi
Radius^2 = 39.62/pi
Radius^2 = 12.62
Solve for radius by taking the square root of both sides
Radius = sqrt(12.62)
Radius = 3.55 cm
Two halfs equal one whole. think of it like this, an orange cut in half leaves you with two halfs, put them together and you have a whole. simple. multiplying by 2 just means adding a number two times.
1 half plus one half= 2halves= 1 whole
1half x 2= 2 halves=1 whole
Answer:
\large \boxed{\textbf{Bowl = 300 g; cup = 200 g}}
Step-by-step explanation:
Let b = the mass of a bowl
and c = the mass of a cup
We have two conditions:

Calculations:

Check:

OK.