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siniylev [52]
4 years ago
6

Problems that require solving the three-dimensional schrödinger equation can often be reduced to related one-dimensional problem

s. an example of this would be the particle in a cubical box. consider a cubical box with rigid walls (i.e., u(x,y,z)=∞ outside of the cube) and edges of length l. the general solution for this problem is
Mathematics
1 answer:
dusya [7]4 years ago
8 0
The wavefunction for a particle in a one-dimension box is a well-known problem, which has as a solution:

Ψ(x) = √(2/l) sin (nπx/l)

When the box has three dimensions, the general solution is simply the multiplication of the solutions for each dimension, therefore:

Ψ(x) = K · sin (n_x·π·x / l) · sin (n_y·π·y / l) · sin <span>(n_z·π·z / l)</span>
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Five thousand three hundred nine divided by forty three
Marizza181 [45]
123.4651163 or rounded to 123.47
4 0
4 years ago
When using the vertical line test to determine if a graph represents a function, the line can only touch the relation
Mamont248 [21]

Answer: The vertical line test is used to determine if a graph of a relationship is a function or not. if you can draw any vertical line that intersects more than one point on the relationship, then it is not a function.

Hope this helps:)

7 0
3 years ago
The length of a rectangle is 2 more than twice the width. The area of the
vlada-n [284]

Answer: w=5 , L= 2+2(5)=12

Step-by-step explanation:

L=2+2W

A= 60

LxW=60, now we will replace the L

(2+2W)(W)=60   we multiply

2w^2+2w=60

2w^2+2w-60=0  we divide by 2 the equation so we can work easier

w^2+w-30=0

find out w using the quadratic equation

we will get 2 solution,

w=5 and another solution is -6, which is not valid, as the side can not be negative

8 0
3 years ago
Can u show me how to solve this problem 0.11 times 0.91
lisov135 [29]

Answer:

0.1001

Step-by-step explanation: Your answer is 0.1001

 0.91

 <u> 0.11</u>

   1011

 0990

<u>00000</u>

0.1001


Hope this helps you!!! :)

3 0
3 years ago
Given f ( x ) = 1 x + 10 , find the average rate of change of f ( x ) on the interval [ 8 , 8 + h ] . Your answer will be an exp
son4ous [18]

Answer: 1

Step-by-step explanation:

f(8+h)=8+h+10=18+h\\\\f(8)=8+10=18

So, the average rate of change is:

\frac{(18+h)-18}{(8+h)-8}=\frac{h}{h}=\boxed{1}

The question is wrong, the expression will not be in terms of h since it is a linear function.

6 0
2 years ago
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