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4 years ago

Is 3[g(x)] = x a linear function?

Mathematics

1 answer:

LenKa [72]4 years ago

7 0

Answer: no

Step-by-step explanation:

Linear functions are straight lines and are also written in the form y=mx+b

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I need some help with this

erastova [34]

I think it’s b or c.

7 0

3 years ago

PLEASE HELP!! 40 POINTS!!

Wewaii [24]

Answer: B

We need to find the difference between the volume of the cone and the volume of the sphere, because it doesn’t contain ice.

Volume of the CONE:
[(pi)r^2(h)] : 3 = [3.14 (16) (6)] : 3 = 100.48in^3

Volume of the SPHERE:
4/3(pi)(r^3) = 4/3(3.14)(0.4)^3 = 0.26794666666 (periodic)

V(cone) - V(sphere) = 100.21205333333 (periodic)

The calculations follow the number [B].

6 0

2 years ago

What is 2.15% of 22?

Burka [1]

Answer:

0.473

Step-by-step explanation:

I used google :) hope this helps!!!!

6 0

3 years ago

Read 2 more answers

If the original bill is 22.50, what will be the final bill after 15% tip is paid ?

Gekata [30.6K]

I believe the answer is 25.88

7 0

3 years ago

Read 2 more answers

PLEASE HELP !! (2/5) -50 POINTS-

Talja [164]

Answer:

$X=\begin{bmatrix}5\\ 14\\ -10\end{bmatrix}$

Step-by-step explanation:

Our approach here is to isolate X, and simplify this solution. We want to begin by subtracting matrix 2, as shown below, from either side - the first step in isolating X. Afterwards we can multiply either side by the inverse of matrix 1, the co - efficient of X, such that X is now isolated. We can then simplify this value.

Given,

$\begin{bmatrix}1&2&3\\ -3&5&5\\ \:\:\:3&-2&-1\end{bmatrix}$ : Matrix 1

$\begin{bmatrix}3\\ -1\\ 8\end{bmatrix}$ : Matrix 2

$\begin{bmatrix}1&2&3\\ -3&5&5\\ 3&-2&-1\end{bmatrix}X+\begin{bmatrix}3\\ -1\\ 8\end{bmatrix}=\begin{bmatrix}6\\ 4\\ 5\end{bmatrix}$ ( Subtract Matrix 2 from either side )

$\begin{bmatrix}1&2&3\\ -3&5&5\\ 3&-2&-1\end{bmatrix}X=\begin{bmatrix}6\\ 4\\ 5\end{bmatrix}-\begin{bmatrix}3\\ -1\\ 8\end{bmatrix}$ ( Simplify )

$\begin{bmatrix}6\\ 4\\ 5\end{bmatrix}-\begin{bmatrix}3\\ -1\\ 8\end{bmatrix} = \begin{bmatrix}6-3\\ 4-\left(-1\right)\\ 5-8\end{bmatrix}=\begin{bmatrix}3\\ 5\\ -3\end{bmatrix}$ ( Substitute )

$\begin{bmatrix}1&2&3\\ -3&5&5\\ 3&-2&-1\end{bmatrix}X=\begin{bmatrix}3\\ 5\\ -3\end{bmatrix}$ ( Multiply either side by inverse of Matrix 1 )

$X=\begin{bmatrix}1&2&3\\ -3&5&5\\ 3&-2&-1\end{bmatrix}^{-1}\begin{bmatrix}3\\ 5\\ -3\end{bmatrix}=\begin{bmatrix}5\\ 14\\ -10\end{bmatrix}$ - let's say that this is Matrix 3. Our solution would hence be Matrix 3.

4 0

3 years ago