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MaRussiya [10]
3 years ago
6

The school band sells tickets to raise money for a trip. The band spends $236 on food and $200 on the tickets. The band sells ea

ch ticket for $15. How many tickets must the band sell to break even? Round up to the next whole ticket number.
A. 13 tickets
B. 16 tickets
C. 30 tickets
D. 29.07 tickets
Mathematics
2 answers:
mina [271]3 years ago
7 0

Answer:

30 tickets

Bottom Left on TTM

C

valina [46]3 years ago
6 0
D., Because 29 x 15 is 435 but if you throw the .07 in the mix you'll have 436.05 which breaks even.
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130% of what is 82.1? (Please show work!)
beks73 [17]
The answer is:  63.1538461538461538 ;  (round to: 63.154) .
_____________________________________________________
130/100  * n = 82.1  ;  Solve for "n" ;
<span>_________________________________________
</span>(1.3) n = 82.1 ; 

n = 82.1 / 1.3 ;

n = 82.1 / 1.3 =   63.1538461538461538  ;  round to 63.154 .
_________________________________________________
3 0
3 years ago
Can someone plz ummmm help me :))))))
OleMash [197]

Answer:

Arithmetric, why do u keep asking the same thing! And how are you doing edpussle on the WEEKEND???

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Step-by-step explanation:

7 0
3 years ago
Cindy bought 1/4 pound of sliced chicken and 7/4 pound of sliced turkey about how did she have in all
yKpoI14uk [10]
Just add the two fractions together 1/4 + 7/4 and you will get 2 so it would be 2 pounds all together
3 0
3 years ago
LA=<br> Round your answer to the nearest hundredth.<br> с<br> B<br> 6<br> 8<br> ?<br> А
lora16 [44]

Answer:

41.41 would be the answer

6 0
2 years ago
Mrs. johnson's and mr. wei's classes are participating in the Meridian School arts and crafts exhibit. Their spaces will be next
Nat2105 [25]

Answer:

See explanation

Step-by-step explanation:

Ms. Johnson space has 48 carpet squares.

Mr. Wei space has 36 carpet squares.

Factorize these two numbers:

48=2\cdot 2\cdot 2\cdot 2\cdot 3\\ \\36=2\cdot 2\cdot 3\cdot 3

All common factors are 1, 2, 3, 4, 6, 12

<u>All possibilities:</u>

1. If Ms. Johnson space width and Mr. Wei space width is 1 carpet, then Ms. Johnson space length is 48 carpets and Mr. Wei space length is 36 carpets.

2. If Ms. Johnson space width and Mr. Wei space width is 2 carpets, then Ms. Johnson space length is 24 carpets and Mr. Wei space length is 18 carpets.

3. If Ms. Johnson space width and Mr. Wei space width is 3 carpets, then Ms. Johnson space length is 16 carpets and Mr. Wei space length is 12 carpets.

4. If Ms. Johnson space width and Mr. Wei space width is 4 carpets, then Ms. Johnson space length is 12 carpets and Mr. Wei space length is 9 carpets.

5. If Ms. Johnson space width and Mr. Wei space width is 6 carpets, then Ms. Johnson space length is 8 carpets and Mr. Wei space length is 6 carpets.

6. If Ms. Johnson space width and Mr. Wei space width is 12 carpets, then Ms. Johnson space length is 4 carpets and Mr. Wei space length is 3 carpets.

4 0
3 years ago
Read 2 more answers
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