Answer:
(i) (f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2
Step-by-step explanation:
The given functions are;
f(x) = x² + 3·x + 2
g(x) = x + 1
(i) (f - g)(x) = f(x) - g(x)
∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1
(f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = f(x) + g(x)
∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3
(f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = f(x) × g(x)
∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2
(f·g)(x) = x³ + 4·x² + 5·x + 2
Answer:
(x + 3)(x - 5)
Step-by-step explanation:
Well to factor x^2-2x-15,
we need to find 2 numbers that multiply to get -15 and add to get -2.
3*-5 = -15
3x + -5x = -2x
x*x = x^2
Factored (x + 3)(x - 5)
<em>Hope this helps :)</em>
The answer is D :)
I hope this helps! Let me know if you need help with anything else! I'd be happy to help in anyway I can! :D
Answer: 1, 3, 5
let x represent the smallest consecutive odd integer
2x + 3 = x + 4
2x - x = 4 - 3
x = 1
therefore the lowest integer is 1, making the other two 3 and 5.