The height of a free falling object is represented by the expression -16t2 + v02 + h0 where v o is the initial velocity of 80 fe
et per second. And h o is the initial height of 25 feet what is the height of the object at t = 2 seconds ( pls no fake answers )
2 answers:
Answer: 45 feet
Explain: don’t really have one I do math in my head so I just knew
Answer:
The height of the object after 3 seconds is 45 feets.
Step-by-step explanation:
The height of an object thrown into the air with an initial upward velocity of 63 feet per second is given as
Where, h(t) is height of the object in feet and t is the time in seconds.
We have to find the height of the object after 3 seconds. So, substitute t=3.
Therefore height of the object after 3 seconds is 45 feets.
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