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kvasek [131]
4 years ago
11

he width and length of a rectangle (in feet)are consecutive odd integers. If the length is increased by 5 feet, the area of the

resulting rectangle is 60 square feet. What is the area of the original rectangle?
Mathematics
1 answer:
Ivanshal [37]4 years ago
3 0

The original area of the rectangle is 35ft^{2}

<u>Explanation:</u>

width = x

length = x + 2

area of the rectangle = x (x+2)

length = x + 2 + 5 = x+7

60 = (x+7) (x)\\60=x^{2} + 7x\\x^{2}  + 7x - 60 =0\\

Solving this equation, we get

x =5ft

So, original  width = 5ft

original length = 5+2ft = 7ft

Thus, original area of the rectangle = 5 X 7ft = 35ft^{2}

Therefore, the original area of the rectangle is 35ft^{2}

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