Question

he width and length of a rectangle (in feet)are consecutive odd integers. If the length is increased by 5 feet, the area of the resulting rectangle is 60 square feet. What is the area of the original rectangle?

Answer 1

The original area of the rectangle is $35ft^{2}$

Explanation:

width = x

length = x + 2

area of the rectangle = x (x+2)

length = x + 2 + 5 = x+7

$60 = (x+7) (x)\\60=x^{2} + 7x\\x^{2} + 7x - 60 =0$

Solving this equation, we get

x =5ft

So, original  width = 5ft

original length = 5+2ft = 7ft

Thus, original area of the rectangle = 5 X 7ft = $35ft^{2}$

Therefore, the original area of the rectangle is $35ft^{2}$