Question

Evaluate the numerical value of the vertical velocity of the car at time t=0. 25s using the expression from part d, where y0=0. 75m, α=0. 95s−1, and ω=6. 3s−1.

Answer 1

The vertical velocity of the car at the given position and time is 4.905 m/s.

The given parameters:

• Initial angular velocity, $\omega_0$ = 6.3 rad/s
• Time of motion, t = 0.25 s
• Vertical displacement, y = 0.75 m
• Angular acceleration, $\alpha = 0.95 \ rad/s^2$

What is vertical velocity?

• This is the linear velocity of an object in a vertical direction.

The angular velocity of an object in a circular motion is given as;

$\omega_f = \omega _0 + \alpha t\\\\\omega _f = 6.3 \ +\ 0.95 \times 0.25 \\\\\omega _f = 6.54 \ rad/s$

The vertical velocity of the car at the given position and time is calculated as follows;

$v = \omega r\\\\v = \omega_f y\\\\v = (6.54 \ rad/s)\times (0.75\ m)\\\\v = 4.905 \ m/s$

Thus, the vertical velocity of the car at the given position and time is 4.905 m/s.

Learn more about vertical velocity here: brainly.com/question/7358392