The kind of shot i will take if asked to take a shot of a landscape area is called; Landscape Shot
<h3>Understanding Landscape Photography</h3>
Landscape photography is defined as the practice of capturing a natural or outdoor scene in an artful or compelling way in order to get the attention the viewer's.
There are different types of making photography but landscape photography is simply one of the most appreciated genres of photography and as such when taking shots of large fields and mountains we will take a landscape shot.
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The minimum number of people who claimed ancestry from all three heritages is : 45
Given that there are 100 relatives
let's assume that 1 relative = 1 room
100 relatives = 100 rooms
Number of relatives with Italian heritage = 90
Number of relatives with German heritage = 80
Number of relatives with swiss heritage = 75
<u>Step 1 : </u>
Fill up the first 90 rooms with Italian heritage relatives
Fill up the remaining 10 rooms with 10 Relatives with German heritage
<u>Step 2 :</u>
Distribute the remaining 70 relatives with German heritage into 70 rooms out of the 90 rooms already occupied by the relatives with Italian heritage
<u>Step 3: </u>
Distribute the 75 relatives with swiss heritage into the 20 rooms occupied by Italian heritage relatives only and<em> </em><u><em>45 rooms</em></u><u><em> occupied by both </em></u><u><em>German and Italian relatives</em></u><u><em> </em></u>and into the 10 rooms occupied by the German heritage relatives
Therefore we can conclude that the minimum number of people who claimed ancestry from all three heritages is : 45
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The value of kb of cyclohexane in the given question is; kb = 2.82 °C/m
<h3>Understanding Molality of a Solution</h3>
Molality of solution = (Number of moles of C₆H₄Cl₂)/(Mass of Cyclohexane)
Now;
Number of moles of C₆H₄Cl₂ = Mass/molar mass = 2g/147 g/mol
Number of moles of C₆H₄Cl₂ = 0.0136 mol
Molality of solution = 0.0136/(22.5 * 10⁻³ kg)
Molality of solution = 0.6 m
Now, to find kb for cyclohexane, we will use the formula;
T_b(solution) - T_b(solvent) = kb × molality of solution
Thus;
82.39 - 70 = kb * 0.6
kb = (82.39 - 70)/0.6
kb = 2.82 °C/m
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