= 1/2kx2
U = potential energy of a spring at a certain position
k = the spring constant, specific to the spring, with units N/m.
x = distance the spring is stretched or compressed away from equilibrium
Potential Energy: Elastic Formula Questions:
1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?
Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:
U = 1/2kx2
U = 1/2(7.50 N/m)(0.40 m)2
U = 0.60 N∙m
U = 0.60 J
3(x-3) = -3x + 39
3x - 9 = -3x + 39
3x + 3x = 39 + 9
6x = 48
x = 48/6
x = 8
In short, Your Answer would be Option C) 8
Hope this helps!
A pays 3/5 x 85 = £51,-
b pays 2/5 x 85= £34,-
So the answer is £51,-
Answer:
1/64
Step-by-step explanation:
1/4*1/4=1/16
1/16*1/4=1/64
this is the same as 1/4^3
Hope this helps
