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AleksAgata [21]
3 years ago
9

Find the missing exponent

Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0
-7 is the missing exponent
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The lateral area of a cylinder is 325 pi inch^2. The radius is 13 in. Find the surface area and volume. Please show all work!!!
USPshnik [31]
Answer:

Surface area =  663π in².
Volume = (676/3)π in² ≈ 225.33 π in²

Explanation:


1) We know the radius and the lateral area.

2) With the radius you can find the areas of the top and the bottom.

For that, you use the formula: 

area of the top = area of the bottom = π r² 


∴ π (13 in)² = 169π in² (each)


3) Then, the surface area is the sum of the lateral area and the two bases (top and bottom)

surface area = lateral area + bottom area + top area = 325π in² + 2×169π in² = 663π in².

3) You  can also find the height of the cylinder.

Use the formula: lateral area = 2π r h


∴ h = lateral area / [2 π r]

⇒ h = 325 π / [ 2π (13) ] = 12.5 in


4) With  the height you can find the volume.

Use the formula: V = (4/3) π r³ 

∴ V = (4/3) π (13 in)³ = (676/3)π in² ≈ 225.33 π in²
8 0
3 years ago
HELP PLS!!!!!!!!!!!!!!!!!!!
Rama09 [41]
Domain: {-5, 7}
Range: {-9, 4, 8}
6 0
3 years ago
In AIJK, the measure of K=90°, IJ = 8.6 feet, and KI = 4.5 feet. Find
azamat

Answer:

58.4

Step-by-step explanation:

delta math give up

3 0
3 years ago
Help please quickly!!!!!!1
IgorLugansk [536]

Answer:

9

Step-by-step explanation:

As per the problem, the given triangle is a right triangle. This is signified by the box around one of its angles, this box states that the angle it is surrounding is a right angle.

Since it is a right triangle, one can use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that; (a^2 + b^2 = c^2), where (a) and (b) are the legs of the right triangle, or the sides adjacent to the right angle. (c) is the hypotenuse or the side opposite the right angle.

Substitute in the given values and solve, note that (a) represents the unknown leg (side).

a^2 + b^2 = c^2\\\\a^2 + (\sqrt{19})^2 = (100)^2\\\\a^2 + 19 = 100

Inverse operations,

a^2 + 19 = 100\\-19\\\\a^2 = 81\\\\a = \sqrt{81}\\\\a = 9

8 0
3 years ago
Hey what's the answer ?<br><br><img src="https://tex.z-dn.net/?f=%28x%20-%20y%29" id="TexFormula1" title="(x - y)" alt="(x - y)"
Varvara68 [4.7K]

Answer:

<em> </em><em>-</em><em>1</em>

Step-by-step explanation:

<em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>The </em><em>value</em><em> of</em><em> x</em><em> </em><em>=</em><em> </em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>The </em><em>value</em><em> of</em><em> </em><em>y </em><em>=</em><em> </em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>we </em><em>need</em><em> to</em><em> find</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>y)</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>so,</em><em> </em><em>put </em><em>the </em><em>value </em><em>of </em><em>above</em><em> </em><em>variables</em><em> </em><em>in </em><em>it</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>hence</em><em>,</em><em> </em><em>(</em><em>1</em><em> </em><em>-</em><em> </em><em>2</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em> </em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>-</em><em> </em><em>1</em><em> </em><em>is </em><em>correct</em><em> answer</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>hope</em><em> it</em><em> helps</em>

3 0
3 years ago
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