Step-by-step explanation:
the mistake was made when the value of cos 3 pi over 2 was calculated.
tan(A-B)= ?since tan=sin/cos
<u>sin</u><u>(</u><u>A-B</u><u>)</u> = <u>sinAcosB-cosAsinB</u>
cos(A-B) cosAcosB+sinAsinB
divide by cos on the RHS
tan(A-B)= <u>tanA-tanB</u>
1+tanAtanB
To find slope you need to use the coordinates of two points on the line. If the coordinates are (x1, y1) and (x2, y2) do y2-y1 / x2-x1 to find the slope.
So far in the equation of a line, y=mx+b, you have the "m" which is the slope.
Plug in the slope, and the x and y values from one of the points and solve for b, which is the y intercept.
Here's an example if the coordinates are (1,4) and (2,6):
6-4/2-1 = 2/1 = 2
The slope is 2.
y = 2x + b
4 = 2(1) + b
4 = 2 + b
4-2 = 2-2 + b
2= b
The full equation is y = 2x + 2
Click on this picture and it'll give you an idea I'm not writing all those numbers
There are two semicircles in the drawing: the arc going clockwise from a to c and the arc going counterclockwise from a to c.
AOB is adjacent to BOC
BOC is adjacent to COD
and
COD is adjacent to AOD
Since COD is 45 degrees, angle AOD is 180 degrees - 45 degrees or 135 degrees.
The circumference of the circle is pi * AC. The length of the arc AD = 135/360 * pi * AC = 1.18 * AC.
Answer:
(cos^2 y) /(1-sin y) = (1 - sin^2 y) / (1-sin y) = ((1-sin y)(1+sin y)) / (1-sin y) = 1+sin y