The property demonstrated is Associative property.
Answer:
Part A: Options D and E
Part B: Disagree
Step-by-step explanation:
Part A:
From the graph attached,
Option A
The object is launched from the ground.
False.
Since, the object is launched from the 5 feet above the ground.
Option B
The flight is symmetric about the line t = 10
False.
Since, the flight is symmetric about the line t = 12
Option C
The object reaches a maximum height of 12 feet.
False.
At t = 12 seconds maximum height of the object = 19.4 feet
Option D
The object is flying in the air during the interval 0 < t < 25.93
True.
Option E
The object reaches its maximum height after 12 seconds of flight.
True.
After 12 seconds object is at the maximum height 19.4 feet.
Therefore, Options D and E are the correct options.
Part B:
From the table attached,
h(4) = 13
h(20) = 13
At t = 4 and 13 seconds height of the object is same.
h(4) = h(20)
But Timothy said h(4) < h(20)
Therefore, disagree with the statement of Timothy.
Answer:
Switch x and y.
Solve for x.
Function can be written as x²+4.
and last one will be 4.
;-)
Step-by-step explanation:
It is at 1 because each space represents 2 units.
-3+(2×2)=1
It is at the point 1.
Multiply fraction (1 1/2) by the # of hours last week (12).
= 1 1/2 * 12
change to improper fraction
= 3/2 * 12
multiply numerators
= (3*12)/2
= 36/2
= 18 hours
ANSWER: D) 18 H
Hope this helps! :)
