a)
y=4 x +(1.6 X 10)
b)
y=4x +16
c)
x=0 y=0+16 (0,16)
x=1 y=4 +16 (1,20) first day it cost $20
x=2 y=8+16 (2,24) second day it cost $24
x=3 y=12+16 (3, 28) third day it cost $28
plot (0,16) , (1,20), (2,24), (3, 28)
i hope this help
<span>At a corner gas station, the revenue R varies directly with the number g of gallons of gasoline sold. If the revenue is $44.50 when the number of gallons sold is 10, find a linear equation that relates revenue R to the number g of gallons of gasoline. Then find the revenue R when the number of gallons of gasoline sold is 15.5.
Solution:
As the question mentioned the direct relationship between the quantities, hence
10 gallons of gasoline sold = $44.50
15.5 gallons of gasoline sold = $x
by cross multiplication, we get that
10x = 15.5 * 44.50
which implies that
x = 68.975
Thus by $</span>68.975 revenue is obtained by selling 15.5 gallons of gasoline.
Answer:
See Below
Step-by-step explanation:
First, isolate x. To do that add 3.5 to each side
x - 3.5 = -3.1
+3.5 +3.5
x= 0.4
18 min per pound
324 min. = X
______ _____
18 1 pound
324 x 1 = 324 324/18= 18 pounds
Cross multiply then divide as above.
Answer:
t= 9, t= -9
Step-by-step explanation:
