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2 years ago

Which fraction is equivalent to 2 10

Mathematics

1 answer:

yawa3891 [41]2 years ago

7 0

Answer:

Fraction Equivalent Fractions

1/5 2/10 4/20

2/5 4/10 8/20

3/5 6/10 12/20

4/5 8/10 16

Step-by-step explanation:

THIS IS ANSWER PLS MARK BRAINLIST

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The average weekly salary of two employees is $5250. One makes $500 more than the other. Find their salaries.

irga5000 [103]

Answer: thier salaries are $5000 and $5500

Step-by-step explanation:

Let the average weekly salary of one employee be =x

And that of the other employee be = x+500

Such that if thier average of their salaries= $5250

So, their total salary= $5250 x 2=10,500

The equation to solve each employee salary becomes

x+x+500=10,500

2x+500=10,500

2x=10,500-500

2x=10,000

x=10,000 /2

x= first employee salary =$5000

second employee = x+500 =$5500

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3 years ago

Hello please help i’ll give brainliest

dlinn [17]

Answer:

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Step-by-step explanation:

As,

The Earth has two basic sources of energy -

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5 0

2 years ago

use the explicit formula an = a1 + (n - 1) * d to find the 500th term of the sequence below. 24,30,36,42,48,... A. 3018 B. 3042

marishachu [46]

Answer:

Option A.

Step-by-step explanation:

The given sequence is

24, 30, 36, 42, 48, ...

It is an AP. Here,

First term = 24

Common difference = 30-24 = 6

The given explicit formula for nth term is

$a_n=a_1+(n-1)d$

where, $a_1$ is first term, d is common difference.

Substitute $a_1=24, d=6 \text{ and }n=500$ in the above formula.

$a_{500}=24+(500-1)(6)$

$a_{500}=24+(499)(6)$

$a_{500}=24+2994$

$a_{500}=3018$

The 500th term of the sequence is 3018.

Therefore, the correct option is A.

3 0

2 years ago

Given:

lisov135 [29]

Answer:

Step-by-step explanation:

6 0

2 years ago

Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin

ozzi

$I=5\int \frac{cos^{4}\theta }{sin\theta }\times cos\theta d\theta \\\\I=5\int \left ( 1-sin^{2}\theta \right )^{2}\times \frac{cos\theta }{sin\theta }d\theta \\put\ \sin\theta =t\\\\dt=cos\theta d\theta \\\\I=5\int\frac{t^{4}+1-2t^{2}}{t}dt\ \ \ \ \ \ \ \ \ \ \because (a-b)^2=a^2+b^2-2ab\\\\I=5\left ( \int t^{3}dt + \int \frac{1}{t} -2\int t \right )dt$

by using the integration formula

we get,

$\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c$

now put the value of t=\sin\theta in the above equation

we get,

$\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c$

hence proved

7 0

2 years ago