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3 years ago

What polygon is shown below? O A. Square O B. Rhombus

Mathematics

1 answer:

Troyanec [42]3 years ago

8 0

I think the answer would be B Rhombus.
Sry if I’m wrong, but I hope this helped!

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What is the true solution to 3 In 2+In 8 = 2 In(4x)? 60f Š O OOO TNT 00

alina1380 [7]

Answer:

x = 2

Step-by-step explanation:

Taking antilogs, you have ...

2³ × 8 = (4x)²

64 = 16x²

x = √(64/16) = √4

x = 2 . . . . . . . . (the negative square root is not a solution)

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You can also work more directly with the logs, if you like.

3·ln(2) +ln(2³) = 2ln(2²x) . . . . . . . . . . . write 4 and 8 as powers of 2

3·ln(2) +3·ln(2) = 2(2·ln(2) +ln(x)) . . . . use rules of logs to move exponents

6·ln(2) = 4·ln(2) +2·ln(x) . . . . . . . . . . . . simplify

2·ln(2) = 2·ln(x) . . . . . . . . . . . subtract 4ln(2)

ln(2) = ln(x) . . . . . . . . . . . . . . divide by 2

2 = x . . . . . . . . . . . . . . . . . . . take the antilogs

4 0

3 years ago

Which of the following expressions is this one equivalent to?

schepotkina [342]

Answer: C. x-2

Step-by-step explanation:

We have the following expression:

$\frac{x^{4} -2x^{3} +x-2}{x^{3}+1}$

Factoring in the numerator:

$\frac{x(x^{3}+1)-2(x^{3}+1)}{x^{3}+1}$

Factoring again in the numerator with common factor $x^{3}+1$ :

$\frac{(x^{3}+1)(x-2)}{x^{3}+1}$

Simplifying:

$x-2$

Hence, the correct option is C. x-2

3 0

3 years ago

a language arts test is worth 100 points there is a total of 26 questions . there are spelling word questions that ae worth 2 po

natka813 [3]

10 question of spelling words and 16 questions of vocabulary are present

Solution:

Let "x" be the number of spelling word questions

Let "y" be the number of vocabulary word question

There is a total of 26 questions. Therefore, we get

number of spelling word questions + number of vocabulary word question = 26

x + y = 26 --------- eqn 1

There are spelling word questions that worth 2 points each and vocabulary word question worth 5 points each

The language arts test is worth 100 points

Therefore, we frame a equation as:

number of spelling word questions x 2 + number of vocabulary word question x 5 = 100

$x \times 2 + y \times 5 = 100$

2x + 5y = 100 --------- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

x = 26 - y ------- eqn 3

Substitute eqn 3 in eqn 2

2(26 - y) + 5y = 100

52 - 2y + 5y = 100

3y = 100 - 52

3y = 48

Substitute y = 16 in eqn 3

x = 26 - 16

Thus 10 question of spelling words and 16 questions of vocabulary are present

4 0

3 years ago

Geraldos sister weighed 7 pounds,6 ounces when the was born how many total ounces did Geraldos sister weigh when she was born

Gekata [30.6K]

118 ounces. 7 × 16 + 6 = 118

4 0

3 years ago

Chu want some points? Answer correctly n ill give em to ya;) 4+7

Andrej [43]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers