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Anastaziya [24]
1 year ago
14

1-tan^2(x)/sec^2 = cos(2x)

Mathematics
1 answer:
LekaFEV [45]1 year ago
3 0

By applying the formula of trigonometric function the right hand side will

be equal to right hand side which is 1-tan^{2} x/sec^{2}x=cos2x.

Given: 1-tan^{2} x/sec^{2}x=cos2x.

Taking right hand side first which is cos2x.

We know that cos2x=1-tan^{2}x/1+tan^{2}x

Now we will solve the left hand side of the equation give which is

1-tan^{2} x/sec^{2}x

=1-tan^{2}x/1+tan^{2}x

[secant square x minus tangent square x is equal to 1]

By putting both values left hand side and right hand side we will find our solution which is :

1-tan^{2}x/1+tan^{2}x=1-tan^{2}x/1+tan^{2}x.

Hence proved

Learn more about trigonometric functions at brainly.com/question/24349828

#SPJ10

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