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Anastaziya [24]
1 year ago
14

1-tan^2(x)/sec^2 = cos(2x)

Mathematics
1 answer:
LekaFEV [45]1 year ago
3 0

By applying the formula of trigonometric function the right hand side will

be equal to right hand side which is 1-tan^{2} x/sec^{2}x=cos2x.

Given: 1-tan^{2} x/sec^{2}x=cos2x.

Taking right hand side first which is cos2x.

We know that cos2x=1-tan^{2}x/1+tan^{2}x

Now we will solve the left hand side of the equation give which is

1-tan^{2} x/sec^{2}x

=1-tan^{2}x/1+tan^{2}x

[secant square x minus tangent square x is equal to 1]

By putting both values left hand side and right hand side we will find our solution which is :

1-tan^{2}x/1+tan^{2}x=1-tan^{2}x/1+tan^{2}x.

Hence proved

Learn more about trigonometric functions at brainly.com/question/24349828

#SPJ10

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Taya2010 [7]

The question is incomplete. Here is the complete question:

The height of a wooden pole, h, is equal to 15 feet. A taut wire is stretched from a point on the ground to the top of the pole. The  distance from the base of the pole to this point on the ground, b. is equal to 8 feet. What is the length of the wire?

Answer:

Length of wire = 17 feet

Step-by-step explanation:

Given:

The height of the wooden pole is, h=15\ ft

The distance from the base of the pole to this point on the ground is, b=8\ ft

Let the length of the wire be 'l'.

Now, consider the triangle formed by the pole, the base, and the wire. The length of the wire is the slant length and hence the hypotenuse of the triangle.

Using Pythagorean theorem, we can find the hypotenuse.

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Plug in the given values and solve for 'l'. This gives,

l^2=15^2+8^2\\\\l^2=225+64\\\\l^2=289\\\\l=\sqrt{289}\\\\l=\pm17

As length can never be negative, we ignore the negative result.

Therefore, the length of the wire is 17 feet.

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Step-by-step explanation:

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