<u>Given</u>:
Given that the radius of the circle is √98 units.
The circle is centered at the point (5.9, 6.7)
We need to determine the equation of the circle.
<u>Equation of the circle:</u>
The general form of the equation of the circle is given by
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
where (h,k) is the center and r is the radius of the circle.
Substituting the center point (h,k) = (5.9, 6.7) and r = √98, we get;
![(x-5.9)^2+(y-6.7)^2=(\sqrt{98})^2](https://tex.z-dn.net/?f=%28x-5.9%29%5E2%2B%28y-6.7%29%5E2%3D%28%5Csqrt%7B98%7D%29%5E2)
Simplifying, we get;
![(x-5.9)^2+(y-6.7)^2=98](https://tex.z-dn.net/?f=%28x-5.9%29%5E2%2B%28y-6.7%29%5E2%3D98)
Thus, the equation of the circle is ![(x-5.9)^2+(y-6.7)^2=98](https://tex.z-dn.net/?f=%28x-5.9%29%5E2%2B%28y-6.7%29%5E2%3D98)