Question

A circle has a radius of square root 98 units and is centered at (5.9, 6.7). Write the equation of this circle. Please help!

Answer 1

Given:

Given that the radius of the circle is √98 units.

The circle is centered at the point (5.9, 6.7)

We need to determine the equation of the circle.

Equation of the circle:

The general form of the equation of the circle is given by

$(x-h)^2+(y-k)^2=r^2$

where (h,k) is the center and r is the radius of the circle.

Substituting the center point (h,k) = (5.9, 6.7) and r = √98, we get;

$(x-5.9)^2+(y-6.7)^2=(\sqrt{98})^2$

Simplifying, we get;

$(x-5.9)^2+(y-6.7)^2=98$

Thus, the equation of the circle is $(x-5.9)^2+(y-6.7)^2=98$