There are a couple of ways to think about this.
1) Weight the speed by the time and compute the weighted average.
(60*2.5 + 75*1.5)/(2.5 + 1.5) = 65.625
Her average rate of speed is 65.625 mph.
2) Consider distance and time.
distance = speed * time
distance₁ = speed₁ * time₁
distance₂ = speed₂ * time₂
total distance = distance₁ + distance₂
total time = time₁ + time₂
And the average speed is given by
average speed = (total distance)/(total time)
Using the above formulas, we have
distance₁ = 60 mi/h * 2.5 h = 150 mi
distance₂ = 75 mi/h * 1.5 h = 112.5 mi
total distance = 150 mi + 112.5 mi = 262.5 mi
total time = 2.5 h + 1.5 h = 4.0 h
average speed = (262.5 mi) / (4.0 h) = 65.625 mi/h
Bette's average rate of speed is 65.625 mph.
Think of asy. as limiting fences to where your graph can travel. If, for example, you graph y = 1/x properly, you'll see that the graph never crosses either the x- or the y-axis. As x increases, your graph will get closer and closer to the line y=0 (which happens to be the horiz. axis), but will not cross it. Similarly, as x approaches x=0, the graph gets closer and closer to the vert. axis, x=0, but will not cross it. Do you see how the asymptotes limit where the graph can go?
Vertical asy. stem only from rational functions and correspond to x-values for which the denominator = 0. As you know, we can NOT divide by zero. Instead, we draw a vertical line thru any x-value at which the rational function is not defined.
Horiz. asy. have to do with the behavior of functions as x grows increasingly large, whether pos. or neg. Go back and re-read my earlier comments on horiz. asy. As x grows incr. large, in the positive direction, the graph of y=1/x approaches, but does not touch or cross, the horiz. asy.I will stop here and encourage you to ask questions if any of this discussion is not clear.
Answer:
8
Step-by-step explanation:
Answer:
P
Step-by-step explanation:
Findings are not the same
3a + 4bc - d = 5a - 8j
<em><u>Add d to both sides.</u></em>
3a + 4bc = 5a - 8j + d
<em><u>Subtract 4bc from each side.</u></em>
3a = 5a - 8j + d - 4bc
<em><u>Subtract 5a from both sides.</u></em>
-2a = -8j + d - 4bc
Divide both sides by -2
a = 
