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Mnenie [13.5K]
2 years ago
8

For each rectangle, write expressions for the length and width and two expressions for the total area. Record them in the table.

Check your expressions in each row with your group and discuss any disagreements.

Mathematics
1 answer:
AveGali [126]2 years ago
7 0

The total area of the rectangles are:

a. Area = 15a

b. Area = 2x

c. Area = 3r

d. Area = 24p

e. Area = 14m

f. Area = 15x + 40

<h3>What is the Area of a Rectangle?</h3>

Th area of a rectangle is given by the formula: length × width

a. width = 3

Length = 5 + a = 5a

Area = 5a × 3 = 15a

b. width = 1/3

length = 6x

Area = 6x × 1/3 = 2x

c. width = r

length = 3

Area = 3 × r = 3r

d. width = 6

length = 4p

Area = 4p × 6 = 24p

e. width = m

length = 6 + 8 = 14

Area = 14 × m = 14m

f. width = 5

length = 3x + 8

Area = (3x + 8)5 = 15x + 40

Learn more about area of rectangle on:

brainly.com/question/25292087

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Geometry help please how do I do these?
trapecia [35]

Answer:

Question 7:

∠L = 124°

∠M = 124°

∠J = 118°

Question 8:

∠Q = 98°

∠T = 98°

∠R = 82°

Question 15:

m∠G = 110°

Question 16:

∠G = 60°

Question 17:

∠G = 80°

Question 18:

∠G = 70°

Step-by-step explanation:

The angles can be solving using Symmetry.

Question 7.

The sum of interior angles in an isosceles trapezoid is 360°, and because it is an  isosceles trapezoid

∠K = ∠J  = 118°

∠L = ∠M

∠K+∠J+∠L +∠M = 360°

236° + 2 ∠L = 360°

Therefore,

∠L = 124°

∠M = 124°

∠J = 118°

Question 8.

In a similar fashion,

∠Q+∠T+∠S +∠R = 360°

and

∠R = ∠S = 82°

∠Q = ∠T

∠Q+∠T + 164° = 360°

2∠Q + 164° = 360°

2∠Q = 196°

∠Q = ∠T  =98°.

Therefore,

∠Q = 98°

∠T = 98°

∠R = 82°

Question 15.

The sum of interior angles of a kite is 360°.

∠E + ∠G + ∠H + ∠F = 360°

Because the kite is symmetrical

∠E  = ∠G.

And since all the angles sum to 360°, we have

∠E +∠G + 100° +40° = 360°

2∠E = 140° = 360°

∠E  = 110° = ∠G.

Therefore,

m∠G = 110°

Question 16.

The angles

∠E = ∠G,

and since all the interior angles sum to 360°,

∠E + ∠G + ∠F +∠H = 360°

∠E + ∠G  + 150 + 90 = 360°

∠E + ∠G   = 120 °

∠E = 60° = ∠G

therefore,

∠G = 60°

Question 17.

The shape is a kite; therefore,

∠H = ∠F = 110°

and

∠H + ∠F + ∠E +∠G = 360°

220° + 60° + ∠G = 360°,

therefore,

∠G = 80°

Question 18.

The shape is a kite; therefore,

∠F = ∠H  = 90°

and

∠F +∠H + ∠E + ∠G = 360°

180° + 110° + ∠G  = 360°

therefore,

∠G = 70°.

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3 years ago
I have 2 congruent, parallel, rectangular bases.
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Answer:

The 3D figure formed is a <u>Cuboid</u><u>.</u>

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Answer:

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Step-by-step explanation:

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