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butalik [34]
2 years ago
5

Do the ratios 18 7 and 2 1 form a proportion?

Mathematics
1 answer:
deff fn [24]2 years ago
5 0

Hi!

There are a few ways we can do this. The first one is this:

The ratios 18:7 and 2:1 can be represented as fractions: \frac{18}{7} and \frac{2}{1}

<em>To see if they are proportions, we can put the fractions in their simplest form and see if they are equal. However, they are already simplified, and we can see that they are </em><u><em>not equal</em></u>.

<em>Therefore they are not proportions.</em>

<em></em>

The second way we can see is to use cross products. Once again we'll put them as fractions, except we'll set them side by side, like so:

\frac{18}{7}  \frac{2}{1}

<em>To see if they are proportions, we simply multiply the diagonals. These would be 18 x 1 and 7 x 2 which equals 18 and 14. These are not equal.</em>

<em />

<em>Therefore they are not proportions.</em>

<em />

Hope this helps! Have a great day! Let me know if you need any other help :D

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a committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer.
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Answer:

\frac{1}{990}

Step-by-step explanation:

<u>The full question:</u>

<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current​ positions?"</em>

<em />

<em />

The permutation of choosing 3 members from a group of 11 would be:

P(n,r) = \frac{n!}{(n-r)!}

Where n would be the total [in this case n is 11] & r would be 3

Which is:

P(11,3) = \frac{11!}{(11-3)!}=\frac{11!}{8!}=11*10*9=990

So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:

1/990

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# Sin θ = 9/15.

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# Sec θ = 5/4

Step-by-step explanation:

by \: using \: pythagorian \: triplets

{a}^{2}  +  {b}^{2}  =  {c}^{2}

{9}^{2}  +  {12}^{2}  =  {c}^{2}

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225 =  {c}^{2}

c = 15.

\sin θ =  \frac{9}{15}

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\csc θ =  \frac{15}{9}

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