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<h3>Final value : x² -9x - 11</h3>════════════════════
<h3>Step by step </h3>2x + 1 = ⅕ × (x² + x - 6)
2x + 1 = ⅕x² + ⅕x - 6/5
1/5x² +1/5x - 2x - 6/5 - 1 = 0
1/5x² -9/5x - 11/5 = 0
x² - 9x - 11 = 0. #times by 5
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#Give me brainliest pls im tired typing all of this
Answer:
A, B, and D
Step-by-step explanation:
Only the functions that have x by itself between the absolute value signs (A, B, and D) are symmetric with respect to the y-axis .
Placing a constant outside the absolute value signs moves the function up or down the y-axis but retains the symmetry.
Adding a constant inside the absolute value signs (as in C and E) moves the axis of symmetry to the left or right of the y-axis.
In the diagram, both A and B are symmetric with respect to the y-axis, but C has been shifted three units to the left.
