Answer:
He could have shut off the power first and de-energize the circuits in order to prevent being electrocuted.
Explanation:
Electrical Safety is very important, <em>especially for those working in such hazardous situations. </em>Almost all our things in the society are electrically-operated, thus it even becomes relevant to have an idea on how we can prevent from obtaining an electrical shock or burns due to faulty electrical tools.
In the worker's scenario above, it is clear that he did not shut off the power at the circuit breaker panel. This is the most important thing that one must include in his plan when attempting to correct an electrical problem. You must find where the electrical switch, fuses and circuit breakers are at first. Once you find their location, you have to turn them off (even if the circuits are of low-voltage).<u> In order to make sure that they are really turned off, test the circuits first. This will help you ensure that they are, indeed, de-energized.</u>
The magnitude of the force of the elevator floor on the person is; 807.13 N
<h3>What is the Magnitude of force? </h3>
We are given;
Weight; W = 0.7 KN
Acceleration; a = 1.5 m/s²
There are only two forces acting on the person: which are his weight W (downward) and the normal force N of the floor against the body (upward). Thus the equilibrium equation here is;
N - W = F
N - W = ma
Here, m is the mass of body, and its value is calculated as;
W = mg
0.7 = 9.81m
m = 0.7/9.81
m = 71.42 kg
Thus;
N - 0.7 = 71.42 * 1.5
N = 0.7 + (71.42 * 1.5)
N = 807.13 N
Read more about Magnitude of Force at; brainly.com/question/9056570
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