1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tamaranim1 [39]
2 years ago
15

A watch company is developing packaging for its new watch. the designer uses octagons with a base area of 30 in2 and rectangles

with a length of 10 in to create a prototype for the new package. what is the volume of the prototype?
SAT
1 answer:
Bess [88]2 years ago
8 0

The volume of the prototype is 300 inches cube.

<h3>How to find volume?</h3>

The volume of the prototype can be found as follows:

volume = base area × height

Therefore,

base area = 30 inches²

height = length = 10 inches.

Hence,

volume of the prototype = 30 × 10

volume of the prototype =  300 inches³.

Therefore, the volume of the prototype is 300 inches³

learn more on volume here: brainly.com/question/16214176

#SPJ4

You might be interested in
What is the universal language in the world
iris [78.8K]

Answer:

english

Explanation:

7 0
2 years ago
Newton’s law of cooling states that for a cooling substance with initial temperature t0, the temperature t(t) after t minutes ca
antoniya [11.8K]

The cooling rate of the substance is approximately 0.0732.

According to the statement, the Newton's law of cooling is defined by the following formula:

T(t) = T_{s} + (T_{o}-T_{s})\cdot e^{-k\cdot t} (1)

Where:

  • T_{s} - Final temperature, in degrees Celsius.
  • T_{o} - Initial temperature, in degrees Celsius.
  • t - Time, in minutes.
  • k - Cooling rate, in \frac{1}{min}.
  • T(t) - Current temperature, in degrees Celsius.

Please notice that substance reaches thermal equilibrium when T(t) = T_{s}, that is when temperature of the substance is equal to the temperature of surrounding air.

If we know that T_{o} = 80\,^{\circ}C, t = 15\,min, T_{s} = 50\,^{\circ}C and T(15) = 60\,^{\circ}C, then the cooling rate of the substance is:

60 = 50 + (80 - 50)\cdot e^{-15\cdot k}

\frac{60-50}{80-50}= e^{-15\cdot k}

\frac{1}{3} = e^{-15\cdot k}

k = -\frac{1}{15}\cdot \ln \frac{1}{3}

k \approx 0.0732

The cooling rate of the substance is approximately 0.0732.

To learn more on Newton's law of cooling, we kindly invite to check this verified question: brainly.com/question/13748261

7 0
2 years ago
Which is the Sl symbol for volume?<br> O m<br> O g<br> O L<br> O K
Tanzania [10]
It’s m3 lol my keyboard doesn’t have the feature to write it professionally but it’s m3
8 0
3 years ago
can someone pls answer my question before this i really need help just picture yourself in this situation
Sergio039 [100]
Why is your question?
5 0
3 years ago
I really need some help so pls someone help me
Burka [1]

Explanation:

I'm ready to help you friend but please share the question....

hope you understood...

8 0
3 years ago
Other questions:
  • Suppose a giant meteor smashes into the Earth and wipes out the majority of life. Describe how succession would help an ecosyste
    14·1 answer
  • A standarized test that colleges use to make admissions decisions is the
    9·2 answers
  • What is 12375/4 simplified
    6·2 answers
  • All prokaryotic and eukaryotic cells have all of the following except
    10·1 answer
  • Molly's hair was 20 inches long.
    14·1 answer
  • Lines a and d are non-coplanar. parallel. perpendicular. skew.
    14·1 answer
  • Blake simplified the expression (startfraction x superscript 12 baseline over x superscript negative 3 baseline endfraction) sup
    6·1 answer
  • What is the median of these data? 48, 60, 22, 84, 36.
    13·1 answer
  • Freezing and thawing water can cause a rock to break down into smaller pieces. Which part of the rock cycle is this an example o
    7·1 answer
  • what do you think about online news these day? does it affect your daily lives? compare between online news and printed news as
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!