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2 years ago

STUDY 1. Simplify the expression below 5p + 14p 4(x - 2) + 6x 2. Evaluate

Mathematics

2 answers:

snow_lady [41]2 years ago

5 0

Answer:

5p + 14p= 19p

4 (x-2)+6x

4x-8+6x

10x-8

melisa1 [442]2 years ago

3 0

Answer:

(11)(B) Simplify numeric and algebraic expressions using the laws of exponents, including integral ... Evaluate the expression for d = -2, d = 0, and d = 1.

Step-by-step explanation:

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which table below represents a non proportional relationship give at least two reasons the justify your choice

Gennadij [26K]

Answer:

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7 0

2 years ago

Help me pleaseeeee will mark brainliest

kaheart [24]

1) 64

2) 1/8

Hope this helps! ;)

8 0

3 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

3 years ago

Help pls! Brainliest!

blagie [28]

Answer:

y =-3000x +12000

Step-by-step explanation:

answer is

1) 12000 is the constant therefore when the number of hours is 0 the tickets are 12000

2) the number of tickets (y) are reducing by 3000 for each hour(x). thus the coefficient of variable x should be -3000 (negative because it is reducing)

8 0

3 years ago

Please send ans in full

Katen [24]

Area of rectangle = l × b

l = 70cm

b = 8cm

Area = 70 × 8 = 560cm²

Area of rectangle = l × b

l = 78cm

b = 15cm

Area = 78 × 75 = 1170cm²

7 0

3 years ago

Read 2 more answers