Help me pleaseeeee will mark brainliest

What are some good notes I can use to study for my algebra exam tomorrow?

zlopas [31]

Answer:

all you need to do is look over your notes continue to partice as much as you can

Step-by-step explanation:

you got this

4 0

3 years ago

Read 2 more answers

Which term best describes a major arc of a circle that has the same starting and ending point

aliya0001 [1]

The Answer is C.Radius

8 0

3 years ago

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Find f(–2) for the function f(x) = 3x2 – 2x 7. −13 −1 1 23

pickupchik [31]

Answer:

16

Step-by-step explanation:

f ( x ) = 3x² - 2x

To find : f ( - 2 )

f ( - 2 ) = f ( x )

Here,

x = - 2

f ( - 2 ) = 3 ( - 2 )² - 2 ( - 2 )

= 3 ( 4 ) - 2*( - 2 )

= 3*4 + 4

= 12 + 4

f ( - 2 ) = 16

8 0

2 years ago

GIVING 100 POINTS

Mekhanik [1.2K]

Answer:

-3x-6<-33 and =3x-65-6

Step-by-step explanation:

8 0

3 years ago

My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the

AVprozaik [17]

Answer:

a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

b) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by: