Answer:
2gx
Step-by-step explanation:
happy to help.
Answer:
![f(x) = 3x^2+8](https://tex.z-dn.net/?f=f%28x%29%20%3D%203x%5E2%2B8)
Step-by-step explanation:
We are given the first derivative of
and the value of
.
To go from the first derivative to the original function, we integrate.
Therefore:
![f(x) = \int {6x} \, dx](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cint%20%7B6x%7D%20%5C%2C%20dx)
To integrate, we add 1 to the power and divide by the new power:
![\int {6x} \, dx = \frac{6x^2}{2} =3x^2+C](https://tex.z-dn.net/?f=%5Cint%20%7B6x%7D%20%5C%2C%20dx%20%3D%20%5Cfrac%7B6x%5E2%7D%7B2%7D%20%3D3x%5E2%2BC)
Because we have an indefinite integral, we have to add the constant,
, to the end.
So: ![f(x) = 3x^2+C](https://tex.z-dn.net/?f=f%28x%29%20%3D%203x%5E2%2BC)
We know
so we can find the constant
.
![f(0)=3(0)^2+C=8](https://tex.z-dn.net/?f=f%280%29%3D3%280%29%5E2%2BC%3D8)
![C=8](https://tex.z-dn.net/?f=C%3D8)
Therefore ![f(x) = 3x^2+8](https://tex.z-dn.net/?f=f%28x%29%20%3D%203x%5E2%2B8)
Given that the two swimmers competed and Ursula's speed is 60 m/min while Andre's speed is 48 m/min. The distance that the Ursula will catch up with Andre will be:
distance=(relative speed)×(time)
relative speed=60-48=12 m/min
the two swimmers met at a distance of:
12×1
=12 meters
Answer:
The current supplies the maximum wattage is 6 Ampere.
Step-by-step explanation:
Given : In a 120-volt circuit having a resistance of 10 ohms, the power W in watts when a current I is flowing through is given by ![W=120I-10I^2](https://tex.z-dn.net/?f=W%3D120I-10I%5E2)
To find : What current supplies the maximum wattage?
Solution :
The equation of power is
![W=120I-10I^2](https://tex.z-dn.net/?f=W%3D120I-10I%5E2)
Derivate w.r.t x,
![W'=120-20I](https://tex.z-dn.net/?f=W%27%3D120-20I)
For critical point put it to zero,
![120-20I=0](https://tex.z-dn.net/?f=120-20I%3D0)
![20I=120](https://tex.z-dn.net/?f=20I%3D120)
![I=\frac{120}{20}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B120%7D%7B20%7D)
![I=6](https://tex.z-dn.net/?f=I%3D6)
Now, again derivate w.r.t I,
It is maximum at I=6 A
Therefore, the current supplies the maximum wattage is 6 Ampere.
Answer:
Brand A
Its easy
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