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beks73 [17]
3 years ago
8

(5x + 6x3 + 2x) - (3x - 2x3 - 7x2) is equivalent to:

Mathematics
1 answer:
Alexus [3.1K]3 years ago
6 0

Answer:

A- 8x^3 + 12x^2 - x

Step-by-step explanation:

The symbol ^ with a 2 is squared and ^ with 3 means cubed.

1. Add a 1 before the parenthesis on both sides. Now, the equation should look like 1(5x^2 + 6x^3 + 2x) -1(3x - 2x^3 - 7x^2).

2. Now we should distribute. 1 × 5x^2 + 1 × 6x^3 + 1 × 2x -1 × 3x + -1 × -2x^3 + -1 × -7x^2.

3. Now the equation should be simplified.

1 × 5x^2 = 5x^2

1 × 6x^3 = 6x^3

1 × 2x = 2x

-1 × 3x = -3x

-1 × -2x^3 + -1 = 2x^3 -1. In this equation, there is a +- sign together, which is the same as a - sign.

-1 × -7x^2 = 7x^2

4. The new equation is 5x^2 + 6x^3 + 2x - 3x + 2x^3 - 1 + 7x^2

5. Now you can combine the like terms. 5x^2 and 7x^2 can be added, so 5x^2 + 7x^2 is equal to 12x^2. Also, 6x^3 and 2x^3 can be added, so 6x^3 + 2x^3 is equal to 8x^3. Lastly, 2x and -3x can be combined, so 2x - 3x is equal to -1x or -x.

6. So, the simplified equation is 12x^2 + 8x^3 -x. You can also write it as 8x^3 + 12x^2 - x. So, A is the answer.

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butalik [34]

The answers to each of the given problems are;

1) Sum of two smallest integers  = 23

2) 3x + 6

3) 7.5 m/s²

<h3>How to find the sum of consecutive Integers?</h3>

1) We are told that sum of 4 consecutive integers is increased by 20 and equals 70. Thus, we have;

x + (x + 1) + (x + 2) + (x + 3) + 20 = 70

4x + 26 = 70

4x = 70 - 26

4x = 44

x = 44/4

x = 11

Thus, sum of two smallest integers = 11 + 11 + 1 = 23

2) Let the consecutive odd numbers be;

x, (x + 2) and (x + 4)

Sum of these consecutive odd numbers is;

x + x + 2 + x + 4 = 3x + 6

3) We are given the equation to find the acceleration as;

(v_final)² - (v_initial)² = 2ad

We are given;

v_final = 40 m/s

v_initial = 10 m/s

d = 100 m

Thus;

40² - 10² = 2a(100)

1500 = 200a

a = 1500/200

a = 7.5 m/s²

Read more about sum of integers at; brainly.com/question/17695139

#SPJ1

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1 year ago
PLEASE HELP ASAP!!
Gala2k [10]

Answer:

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4 0
2 years ago
Answer this pls..................​
Sindrei [870]

Answer:

so we know:

total of 20 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

1 2 3 4 5 6 7 8

3 are in all of them

1 2 3

1) underline the main 3

total of 20 students

<u>1 2 3 </u>4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

<u>1 2 3</u> 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

<u>1 2 3 </u>4 5 6 7 8

2) lets bold the physics students, if you are in physics you have to do chem so that means 8 of the chem students also take physics.

total

<u>1 2 3 </u>4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry

<u>1 2 3</u> 4 5 6 7 8 9 10 11 12 13 14

physics

<u>1 2 3 </u>4 5 6 7 8

3) now we bring biology into the "equation"

off the bat we know 3 are definitely in Biology.

so if 4 study ONLY biology we can cross them off our list see the {}

total

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} 13 14

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u>

<u />

4) so we have a total of 20 students, 3 in all of the classes <u>(underlined)</u>, 8 in physics (bolded). If there 14 in chemistry, 4 take ONLY chemistry {}, 8 take chemistry as well (bolded), that leaves two students, so they must belong in biology. lets<em> italicise</em> them.

total

<em><u>1 2 3 </u></em>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 16 17 18 19 20

chemistry

<em><u>1 2 3</u></em><em> </em>4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<em><u>1 2 3</u></em><u> </u>4 5 6 7 8

biology

<em><u>1 2 3 </u></em><em> 13 14</em>

<u />

5) out of our total of 20 students we know 14 of the students classes, so the remaining six must be in biology.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u><em>13 14</em> 15 <em>16 17 18 19 20</em>

6) so that was our "diagram" so now lets count how many are in chemistry and biology but NOT physics.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>-1 2 3</u> 4 5 6 7 8- {9 10 11 12} <em>13 14</em>

physics

<u>-1 2 3 </u>4 5 6 7 8-

biology

<u>-1 2 3 -</u><em>13 14</em> 15 <em>16 17 18 19 20</em>

there are 14 students in chemistry and 11 in biology, 5 of them are in both classes so 14-5= 9 and 11-5= 6 9+6=16. BUT 8 of those sixteen are also in -physics- so we arent counting them, we put those students in dashes. so lets count the students out of the dashes. so<em> twelve</em> of them are in chemistry and biology but not physics.

7) so how many are in just biology but not the other classes? lets look at the graph.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u><em>13 14</em> 15 <em>16 17 18 19 20</em>

in the class of biology students 1 2 3 13 and 14 take other classes that leaves students 15 16 17 18 19 and 20. so 6 students take ONLY biology.

sorry its long but i hope this helps!

3 0
3 years ago
. <br> Simplify by using the Distributive Property<br> 4(4f-2g)
Bad White [126]

Answer:

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den301095 [7]

Answer:

8 and 7

Step-by-step explanation:

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